2 What is the correct sequence of steps for the preparation of a pure sample of copper(II) sulfate
crystals from copper(II)oxide and sulfuric acid?
A dissolving → crystallisation → evaporation - filtration
B dissolving → evaporation filtration → crystallisation
Cdissolving → filtration - crystallisation - evaporation
D dissolving + filtration → evaporation → crystallisation

Answers

Answer 1

Answer:

The correct answer is - B. dissolving → evaporation filtration → crystallisation

Explanation:

The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:

step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.

step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir

step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.

Step 4. leave the rest filtrate to crystallize.

Copper (II) Oxide  {CuO (s)}  +  Dilute Sulfuric Acid {H2SO4 (aq)}   →  Copper (II) Sulphate {CuSO4 (s)}   +  Water {H2O}

Answer 2

The correct sequence of steps for the preparation of a pure sample of copper(II) sulfate crystals from copper(II) oxide and sulfuric acid is dissolving → evaporation filtration → crystallisation.

Which form is the purest?

Purest form of any substance is the crystalline form, if we get the compound in the crystalline form from any extraction then we get a pure sample.

Crystals of copper(II) sulfate, will get from copper(II) oxide and sulfuric acid through following steps:

First we put sulfuric acid in a beaker and then we warm in water bath.Then we add some powder of copper(II) oxide to the beaker, and will continue this adding till it is in excess.Then we filter the mixture and pour the filtrate of copper(II) sulfate into an evaporating basin and heat the solution evaporate half of the water.Then we pour the above solution into an evaporating basin & leave to allow all water to evaporate, and finally get the crystals of copper(II) sulfate.

Hence, option (B) is correct.

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Related Questions

1. How many grams of potassium chloride (KCI)
can be dissolved at 10°C?

Answers

Answer:

At 10 ∘C , the solubility of potassium chloride is measured to be 31.2⋅g per 100⋅g of water.

Explanation:

1) ____C3H8 + ____O2 → ____CO2 + ____H2O

Answers

C3H8 + 5O2 → 3CO2 + 4H2O

What's the partial pressure of hydrogen in a gas mixture if its mole fraction is 0.1 and the total pressure is 325 torr?

Question 15 options:



325 torr




32.5 torr




100 torr




65 torr

Answers

I think it’ll be 32.5 torr

4 grams of N is how many moles of N?

Answers

Answer:

0.285577616426424

Explanation:

Hope this helps!

In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in the ground state of phosphorus atom! Select one of the answers below that represents this number.
Group of answer choices

1

4

3

0

2

Answers

Answer:

Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer

Explanation:

Hope this helps :)

93 Points!!! Which of the following join together to form molecules?

Atoms
Organisms
Organs
Tissues

Answers

Answer:

Atoms

Explanation:

Atoms are the smallest thing meaning they form molecules which are made of atoms.

Also, your question is not 93 points but whatever lol.

Answer:

Atoms

Explanation:

I took the test

Draw the atomic structure with electronic configuration of Potassium​

Answers

Answer:

Explanation:

i try to help you

✧Kindly see the attached picture! ☄

♪ Hope I helped! ♡

[tex] \star[/tex] Best regards! ツ

☞ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✎

Which of the following polyatomic ions will form an ionic compound with a single sodium ion?

CO3 2-
HCO3 1-
SO4 2-
SO3 2-

Answers

Answer:

Option B, HCO3 1-

Explanation:

The valence of Sodium ion is +1 and the valence of HCO3 is -1. Thus, sodium ion has an extra electron to be donated to complete its outer shell  while HCO3 needs an electron to complete its outer shell

Hence Na will combine with HCO3 to form NaHCO3

Option B is correct

The polyatomic ion which will form an ionic compound with a single sodium ion is; HCO3 ¹-

In chemical bonding between ions;

The major criteria is a balance of charges within the compound formed.

As such, all polyatomic ions in the option are di-ionic except for HCO3 1- which can perfectly form an ionic compound with 1 single sodium ion.

Read more on ionic compounds:

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ASAP. Which process represents a physical change?
1.Roasting a marshmallow over a camp fire
2.Melting chocolate in a pan on the stove
3.Bruising of a banana's skin after dropping on the floor
4.Bubbling due to an antacid tablet in vinegar

Answers

Melting chocolate is a physical change .

What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.

Answers

Answer:

5.6 m/s

Explanation:

Given,

First number = 13.254 m/s

Second number = 7.7 m/s

We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s

The difference between them is given by :

D = 13.3 - 7.7

= 5.6 m/s

Hence, the difference of the two numbers is 5.6 m/s.


Mr. Ragusa asks Hassan to make silver crystals from the following reaction.
2AgNO3 + Cu --> Cu(NO3)2 + 2Ag
Mr. Ragusa gives Hassan 51 g of silver nitrate to conduct the experiment. Hassan gives Mr. Ragusa 20 g of
silver crystals. What was Hassan's percent yield for his experiment?
Please round your answer to 2 decimal places

Answers

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

Explain the difference between a mixture of two substances and a chemical compound formed by them​

Answers

Answer:

mixtures are physically combined structures that are separated into their original components. A chemical substance is composed of one type of atom or molecule. A mixture is composed of different types of atoms or molecules that are not chemically bonded.

Explain:

yw

ask your mom and your family

what charge does copper have?

Answers

Answer: 1+charge

Explanation: hoped this helped:)

How many molecules are in 3 moles of CO2?
O A. 5.418 x 1024
OB. 1.806 x 1024
O C. 6.02 x 1024
O D. 1.806 x 1023

Answers

Answer:

1.806 × 10²⁴

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

1.806 × 10²⁴

Hope this helps you

Answer: OB. 1.806 x 1024

Explanation:

1. Write formulas for the binary ionic compounds formed between
the following elements:
a. potassium and iodine d. aluminum and sulfur
b. magnesium and chlorine e. aluminum and nitrogen
C. sodium and sulfur

Answers

It’s c hope the helps hav eahlsuieoey owand and please add a good day please add the answers please add me plz plz

The formulas for the binary ionic compounds are:

a. potassium and iodine: KI.b. magnesium and chlorine: MgCl₂.c. sodium and sulfur: Na₂S.d. aluminum and sulfur: Al₂S₃.e. aluminum and nitrogen: AlN.

We want to write the formulas of different binary ionic compounds. to do so, we need to consider the octet's rule.

What is the octet's rule?

The octet's rule establishes that atoms will lose, gain or share electrons to achieve the electron configuration of the nearest noble gas (8 valence electrons except for He with 2).

a. potassium and iodine

K has 1 valence electron so it will lose 1 electron to form K⁺. I has 7 valence electrons so it will gain 1 electron to form I⁻. The neutral compound between K⁺ and I⁻ is KI.

b. magnesium and chlorine

Mg has 2 valence electrons so it will lose 2 electrons to form Mg⁺². Cl has 7 valence electrons so it will gain 1 electron to form Cl⁻. The neutral compound between Mg⁺²⁺ and Cl⁻ is MgCl₂.

c. sodium and sulfur

Na has 1 valence electron so it will lose 1 electron to form Na⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Na⁺ and S⁻² is Na₂S.

d. aluminum and sulfur

Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Al³⁺ and S⁻² is Al₂S₃.

e. aluminum and nitrogen

Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. N has 5 valence electrons so it will gain 3 electrons to form N³⁻. The neutral compound between Al³⁺ and N³⁻ is AlN.

The formulas for the binary ionic compounds are:

a. potassium and iodine: KI.b. magnesium and chlorine: MgCl₂.c. sodium and sulfur: Na₂S.d. aluminum and sulfur: Al₂S₃.e. aluminum and nitrogen: AlN.

Learn more about binary compounds here: https://brainly.com/question/7960132

Which of the following statements is true?

Answers

Answer:

option first is right answer

Muriatic acid is often used to remove rust. A solution of muriatic acid, HCl, reacts with Fe203 deposits on
industrial equipment. How many liters of 5.00 M HCl would be needed to react completely with 339 g
Fe203?

Answers

Answer:

2.54 L

Explanation:

Step 1: Write the balanced neutralization equation

6 HCl + Fe₂O₃ → 3 H₂O + 2 FeCl₃

Step 2: Calculate the moles corresponding to 339 g of Fe₂O₃

The molar mass of Fe₂O₃ is 159.69 g/mol.

339 g × 1 mol/159.69 g = 2.12 mol

Step 3: Calculate the moles of HCl that react with 2.12 moles of Fe₂O₃

The molar ratio of HCl to Fe₂O₃ is 6:1. The reacting moles of HCl are 6/1 × 2.12 mol = 12.7 mol

Step 4: Calculate the volume of HCl

12.7 moles are in 5.00 M (5.00 mol/L) HCl. The required volume is:

12.7 mol × 1 L/5.00 mol = 2.54 L

What is the pH of a solution that has a hydrogen ion concentration of 6.9*10^-4?

Answers

The pH would be 3.16 because the formula for finding the pH from a H± ion is pH = -log [H±]

So with that formula, you first have to substitute the H± with your numbers which in this case is 6.9 × 10^-4.

It should like this:

pH = -log (6.9 × 10^-4)

And lastly, just calculate.

pH = 3.16

Hope that helps, do let me know if you need more help in understanding this!

When you draw a bow'across a violin string, which kind of wave is created in
the air surrounding the string?
A. surface
B. electromagnetic
C. longitudinal
D. Transverse

Answers

Answer:

C

Explanation:

Answer: C. Longitudinal

Explanation: A P 3 X

What is biocapacity?

PLZZ HELP TY

Answers

Answer:

Explanation:

The biocapacity or biological capacity of an ecosystem is an estimate of its production of certain biological materials such as natural resources, and its absorption and filtering of other materials such as carbon dioxide from the atmosphere.

Answer: the capacity to produce biological materials and absorb wastes materials by or from humans in an ecosystem

Calculate the amount (in moles) of magnesium in 1.23 g.

Answers

Answer

0.32 is that answer

Explanation:

you just use the calculator

What is the value of for this aqueous reaction at 298 K?
A+B↽⇀C+D
ΔG°=12.86 kJ/mol
K=

Answers

Answer:

Kc = 0.5951 (4 sig. figs.)

Explanation:

For A + B ⇄ C + D at standard thermodynamic conditions (298K, 1atm)

ΔG = ΔG° + R·T·lnQ => 0 = ΔG° + R·T·lnKc => ΔG° = - R·T·lnKc

=> lnKc = - ΔG°/R·T

ΔG° = +12.86 Kj/mol

R = 8.314 Kj/mol·K

T = 298K

lnKc = - (+12.86Kj) / (8.314Kj/mol·K)(298K) = - 0.519 mol⁻¹

Kc = e⁻⁰°⁵¹⁹ mol⁻¹ = 0.5957 mol⁻¹ (4 sig. figs.)

Enter an equation showing how this buffer neutralizes added aqueous acid (HI). Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Answer:

[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]

Explanation:

Hello there!

In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:

[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]

Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.

Best regards!

Answer:

the above answer is wrong

Explanation:

its really not but the mastering chemistry says it is

if u mix 10ml of 70%ethanol with 20ml of 80% ethanol with 50ml water what is the concentration of the resulted solution

Answers

Answer:

29% is the final concentration

Explanation:

To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:

Volume ethanol / Total volume * 100

Volume ethanol:

10mL * 70% = 7mL ethanol

+

20mL * 80% = 16mL ethanol

= 23mL ethanol

Total volume:

10mL + 20mL + 50mL = 80mL

Concentration:

23mL / 80mL * 100

= 29% is the final concentration

What is the value of for this aqueous reaction at 298 K?

A+B↽⇀C+D ΔG°=12.86 kJ/mol

K=

Answers

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

Where ΔG is Gibbs free energy = 12.86kJ/mol

R is gas constant = 8.314x10⁻³kJ/molK

T is absolute temperature = 298K

And K is equilibrium constant.

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

The equilbrium constant is 179.6

If I have 100 mL of oil in a container and 100 mL of water in another
conta in er Which container wouldhave more mass?

Answers

Answer:

The answer is 200mL each amount have the same mass

Explanation:

100mL +100ML= 200mL mass in each container

Answer:

200ml

Explanation:

An aqueous solution was made by dissolving 0.543 g of an unknown, monoprotic acid into 25.00 mL of water in an Erlenmeyer flask. After an acid/base indicator was added, 41.21 mL of 0.150 M NaOH was used to reach the end point.
a)Find the molar mass of the acid.
b)Determine the identity of the acid based on the following data:

PLEASE HELP ME

Answers

Answer:

a. 87.8g/mol is the molar mass of the acid.

b. The answer is in the explanation.

Explanation:

To solve this question we must find the moles of the monoprotic acid using the reaction with NaOH (1mole of monoprotic acid reacts with 1 mole of NaOH). With the moles and the mass of the unknown we can find the molar mass.

Moles of NaOH added:

0.04121L * (0.150moles / L) = 6.1815x10⁻³ moles NaOH = Moles monoprotic acid

Molar mass is:

0.543g / 6.1815x10⁻³ moles = 87.8g/mol is the molar mass of the acid

b. I can't see the image you are giving because has a low resolution. But the identity of the acid can be obtained because the acid:

Has the same molar mass.

Is a monoprotic acid.

(a) The molecular mass of the unknown monoprotic acid will be 87.84 g/moles.

(b) The acid can be butyric acid, as it is a monoprotic and have mass near about 87.84 g/mol.

(a) The endpoint by the addition of NaOH has been reached when the monoprotic acid has been completely utilized. Since the NaOH has been monobasic. The moles of NaOH will be equal to the moles of acid.

Moles of NaOH = moles of acid

The molarity of NaOH = 0.15 M

Volume of NaOH = 41.21 ml

Molarity = [tex]\rm \dfrac{moles}{volume\;(L)}[/tex]

Moles = molarity [tex]\times[/tex] volume (L)

Moles of NaOH = 0.15 [tex]\times[/tex] 0.04121 L

Moles of NaOH = 0.00618 moles

Moles of NaOH = moles of acid

moles of acid = 0.00618 moles.

Mass of acid dissolved = 0.543 grams

Molecular weight of acid = [tex]\rm \dfrac{weight}{moles}[/tex]

Molecular weight of acid = [tex]\rm \dfrac{0.543}{0.006815}[/tex]

Molecular weight of acid = 87.84 g/moles.

(b) The acid with the molecular mass of 87.84 g/mol with being the monoprotic acid can be butyric acid. The butyric acid has a molecular weight of 88 g/mol.

For more information about monoprotic acid, refer to the link:

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Calculate the molar mass of ZnCr04

Answers

Answer:

181.403 g/mol is the answer as it is Zinc chromate

Explanation:

Answer:

181.403 g/mol

Explanation:

Molar mass of ZnCrO4 = 181.3737 g/mol. This compound is also known as Zinc Chromate. Convert grams ZnCrO4 to moles or moles ZnCrO4 to grams. 65.38 + 51.9961 + 15.9994*4

The chemical formula for sodium citrate is Na3C6H5O7. Which statement is true? Sodium citrate is a compound with a total of 21 atoms. Sodium citrate is an element with a total of 21 atoms. Sodium citrate is a compound with a total of 4 atoms. Sodium citrate is a compound with a total of 21 atoms, each of a different element.

Answers

Answer:

Sodium citrate is a compound with a total of 21 atoms

Ionisation enthalpy across the group (increase or decrease)

Give reasons??​

Answers

Answer:

As we move from left to right across a period, the ionization energy of elements increases. This is due to the decrease in the size of atoms across a period.

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Ionization enthalpy (IE) is the energy required to remove the highest-energy electron from a neutral atom. In general, ionization energy increases across a period and decreases down a group.So, for your question IE decreases down the group.

____________________

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