Answer:
77.2805 μF
Explanation:
Given data :
V = 2460 V
Q = 191 Kva
Calculate the size of Each capacitor
first step : calculate for the value of Xc
Q = V^2/ Xc
Xc ( capacitive reactance ) = V^2 / Q = 2460^2 / ( 191 * 10^3 ) = 31.683 Ω
Given that 1 / 2πFc = 31.683
∴ C ( size of each capacitor ) = [tex]\frac{1}{2\pi *65 *31.683}[/tex] = 77.2805 μF
4. Oil system cleaning products should not use solvents because:
A) O Solvents smell bad
B) Solvents are completely removed during the service
CO Solvents have no impact on dirt and debris
DO Solvents can damage certain plastics and rubbers found in the engine
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Answer:
Solvents can damage certain plastics and rubbers found in the engine
Explanation:
"Como define al ser Humano, la Religión, la biología y la filosofía." y es religion Y urgenteeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
Los seres humanos siempre han tenido la necesidad de explicar y comprender los hechos sobre el mundo, ellos mismos y la naturaleza. La religión se configura como un conjunto de creencias comunes a una comunidad, que busca conectar al hombre con una fe en una divinidad superior que explique una visión y construcción del mundo. En sentido antropológico, la religión es una construcción evolutiva de parámetros sociales y dogmáticos como búsqueda de la creación de un sentido de pertenencia social, además de la búsqueda de la comprensión de uno mismo y del desarrollo espiritual.
La biología y la filosofía surgen como conceptos amplios que buscan explicar otros conceptos sobre la ciencia de manera sistemática, diferente a buscar una comprensión del mundo a través de la religión. La filosofía como concepto de que el hombre puede comprender el mundo a través de sus propias visiones y descubrimientos, desarrollando el pensamiento crítico y la búsqueda del conocimiento, que desarrolló las ciencias, entre ellas la biología que ayudó en la comprensión de parámetros esenciales para la calidad de vida humana, como la medicina por ejemplo.
Entonces hay una convergencia de los conceptos de religión, biología y filosofía, y es posible que el hombre crea en cada uno sin que el otro concepto se vea afectado.
A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as heat to boiler tubes that pass through the furnace. The combustion products pass from the furnace to a stack at 6500C. Water enters the boiler tubes as a liquid at 200C and leaves the tubes as saturated steam at 20 bar absolute. Calculate the rate (kg/h) at which steam is produced.
The rate at which steam is produced is equal to 701 kg/hour.
What is a Boiler?A Boiler may be characterized as a type of device or instrument that significantly transforms water into steam. There are two types of boiler are found. They are water tube boilers and fire tube boilers.
According to the question,
The power generated by combustion, W = 813kW.
The efficiency of the boiler, η = 65% = 0.65.
Temperature, To = 650°C.
Water enters the boiler tubes as a liquid, T1 = 20°C.
Water leaves the tubes as saturated steam, P2 = 20 bar.
The enthalpy of water at 20°C, [tex]h_1[/tex] = 83.9kJ/kg.
The enthalpy of water at 20 bar pressure, [tex]h_2[/tex] = 2797.29kJ/kg.
Enthalpy change can be calculated by ΔH = [tex]h_2-h_1[/tex]
= 2797.29kJ/kg - 83.9kJ/kg = 2713.3 kJ/kg.
The total energy that can be developed can be calculated by the formula:
Q = W × η = 813 × 0.65 = 528.45 kW.The mass of the flow rate of the rate at which steam is produced is calculated by the following formula:
[tex]m^.[/tex] = Q/ΔH= 528.45 kW/2713.3 kJ/kg.
= [tex]\frac{528.45kW }{2713.3kJ/kg} *\frac{3600kJ/h}{1kW}[/tex] = 701 kg/hour.
Therefore, the rate at which steam is produced is equal to 701 kg/hour.
To learn more about Boilers, refer to the link:
https://brainly.com/question/15421700
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If a soil has e=0.72, moisture content = 12% and Gs=2.72, find the weight of water in KN/m3 to be added to make the soil saturated.
Answer:
453 KN/m^3 of water should be added make the soil saturated.
Explanation:
As we know
Gs * w = S*e
S = Gs * w/e
S = 2.72 * 0.12/0.72 = 0.453
The amount of water to be added
0.453 *1000/10 = 453 KN/m^3
Can anyone tell me all the corrects answers to these? I’m sorry if this is the wrong subject I’m not sure what to put it under but I really need help!
Answer:
Crankshaft position sensor - F I can't quite make out the letter but it's the thing at the bottom almost touching the notched wheel.
Coil Module - B
Knock Sensor - D
Coil Pack -E
Fuse Block - A
Powertrain Control Module - C
What distinguishes the research, investigation, and analysis phase from later phases of the historical preservation process?
It involves careful attention to the history of the structure.
It is the only phase that does not involve construction.
It is primarily involved with fact finding.
It is the only phase that does not involve design.
Answer:
c
Explanation:
A CUSTOMER BRINGS HER CAR INTO THE
SHOP WITH A COMPLAINT THAT BOTH
HEADLIGHTS ARE NOT WORKING.
TECHNICIAN A SAYS TO CHECK THE CONDITION OF THE BULBS FIRST. TECHNICIAN B CHECKS THE FUSE IN THE HEADLIGHT CIRCUIT & THEN TESTS THE OPERATION OF THE HEADLIGHT SWITCH WHO IS CORRECT AND WHY ?
HELP ME ASAP
a bc if the bulbs are in a bad conditio. than u know that u dont have to remove it but only repair it.
A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was 5 in.2 and that approximately 2.3 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 200 mpy for this alloy in seawater, estimate the time of submersion in years. The density of steel is 7.9 g/cm3.
Answer:
the estimated time of submersion is 17.7 years
Explanation:
Given the data in the question;
estimate the time of submersion in years.
we write down the relation between time of submersion and corrosion penetration as follows;
CPR(mpy) = K × W(mg) / [ A(in²) × p(g/cm³) × t(hr) ]
we solve for t
t = (K × W) / ( AP × CPR )
given that;
Area A = 5 in²
W = 2.3 kg = 2.3 × 10⁶ mg
density of steel p = 7.9 g/cm³
CPR = 200
we know that K is 534
so we substitute
t = (534 × 2.3 × 10⁶ mg) / ( 5 in² × 7.9 g/cm³ × 200 mpy )
t = 1,228,200,000 / 7900
t = 155468.3544 hr
t = 155468.3544 hr × ( 1 yrs / ( 365 × 24 hrs )
t = 17.7 years
Therefore, the estimated time of submersion is 17.7 years
A total knee replacement experiences a spectrum of loading events, some rapid and some nearly steady state (but for a limited duration). Estimate the duration of the possible loading events, and compute the Deborah number for each, assuming a transition time for the polymer bearing of one day. Are any of these expected to occur in a fluid-like regime
Answer: your question is quite vague hence i will just give you the general answer regarding your question
answer : Deborah number = time of relaxation / time of observation
Explanation:
Estimate of the duration of the possible loading events
to estimate the duration of the possible loading events will first determine the Deborah number as shown
Deborah number = time of relaxation / time of observation
lets assume; Time of observation = 1 and time of relaxation = 1 day
Deborah number is dimensionless and it is used to determine viscoelastic behavior of a material hence the viscoelastic response during observation time is proportional to Deborah number
If a nurse does not agree to the discipline set due to a complaint made against this nurse, after reviewing the proposed agreed order, they can request a
Taking the convection heat transfer coefficient on both sides of the plate to be 860 W/m2 ·K, deter- mine the temperature of the sheet metal when it leaves the oil bath. Also, determine the required rate of heat removal from the oil to keep its temperature constant at 45°C.
Answer:
Hello your question is incomplete attached below is the complete question
answer :
a) 95.80°C
b) 8.23 MW
Explanation:
Convection heat transfer coefficient = 860 W/m^2 . k
a) Calculate for the temp of sheet metal when it leaves the oil bath
first step : find the Biot number
Bi = hLc / K ------- ( 1 )
where : h = 860 W/m^2 , Lc = 0.0025 m , K = 60.5 W/m°C
Input values into equation 1 above
Bi = 0.036 which is < 1 ( hence lumped parameter analysis can be applied )
next : find the time constant
t ( time constant ) = h / P*Cp *Lc --------- ( 2 )
where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C
Input values into equation 2 above
t ( time constant ) = 0.10092 s^-1
Determine the elapsed time
T = L / V = 9/20 = 0.45 min
∴ temp of sheet metal when it leaves the oil bath
= (T(t) - 45 ) / (820 - 45) = e^-(0.10092 * 27 )
T∞ = 45°C
Ti = 820°C
hence : T(t) = 95.80°C
b) Calculate the required rate of heat removal form the oil
Q = mCp ( Ti - T(t) ) ------------ ( 3 )
m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s
Cp = 434 J/kg°C
Ti = 820°C
T(t) = 95.80°C
Input values into equation 3 above
Q = 8.23 MW