45° × π/180 = 0,7854 rad
ω = θ /t
ω = 0.7854 / 0.75 = 1.0472 rad/s
help, please
1.) What is the momentum of a 2,000 kg car moving at 24 m/s?
a.) 48,000 kg m/s
b.) 83.3 kg m/s
c.) 0.0012
--------------------
2.) What is the momentum of a 4.5 kg bowling ball moving at 7 m/s?
a.) 31.5 kg m/s
b.) 0.64 kg m/s
c.) 1.56 kg m/s
Answer:
A and A
Explanation:
see paper for work! :)
A car bounces up and down on its springs at 1.0 Hz with only the driver in the car. Now the driver is joined by four friends. The new frequency of oscillation when the car bounces on its springs is
The new frequency of oscillation when the car bounces on its springs is 0.447 Hz
Frequency of oscillation of spring
The frequency of oscillation of the spring is given by f = (1/2π)√(k/m) where
k = spring constant and m = mass on springNow since k is constant, and f ∝ 1/√m.
So, we have f₂/f₁ = √(m₁/m₂) where
f₁ = initial frequency of spring = 1.0 Hz, m₁ = mass of driver, f₂ = final frequency of spring and m₂ = mass on spring when driver is joined by 4 friends = 5m₁So, making f₂ subject of the formula, we have
f₂ = [√(m₁/m₂)]f₁
Substituting the values of the variables into the equation, we have
f₂ = [√(m₁/m₂)]f₁
f₂ = [√(m₁/5m₁)]1.0 Hz
f₂ = [√(1/5)]1.0 Hz
f₂ = 1.0 Hz/√5
f₂ = 1.0 Hz/2.236
f₂ = 0.447 Hz
So, the new frequency of oscillation when the car bounces on its springs is 0.447 Hz
Learn more about frequency of oscillation of spring here:
https://brainly.com/question/15318845
1. A Capacitor c =5.31 nF, is made of two Parallel square Plates seperated by distance d = 5mm. Find the Area. please ans this, i will give brainliest
We know that,
[tex]\huge ➸ C = ϵ₀ \frac{A}{d} [/tex]
C⤏Capacitanceϵ₀⤏permittivity of free space constantA⤏Area of capacitor platesd ⤏distancegiven ↷
C⤏5.31 nF = 5.31 x 10^-9ϵ₀⤏8.85 x 10^-12 F/m A⤏Area of capacitor platesd ⤏5mmto find ↷
The Areasolution ↷
[tex]\begin{gathered}➸ C = ϵ₀ \frac{A}{d} \\ \end{gathered} [/tex]
[tex]\begin{gathered}➸ A = \frac{Cd}{ϵ₀} \\ \end{gathered} \\ [/tex]
[tex]\begin{gathered}➸ A = \frac{5.31 \times {10}^{ - 9} \times 5 }{8.85 \times {10}^{ - 12} } \\ \end{gathered} \\ [/tex]
[tex]➸ A =3 \times {10}^{3} {mm}^{2} [/tex]
[tex]➸ A =3 {m}^{2} [/tex]
Hence, the area is 3m²
Answer:
Explanation:
The capacitance of two parallel square plates of area A and separated by distance d is given as:
C = ε(A/d) where ε is the permittivity of the dielectric material
For air, ε = 8.854x10^(-12) F/m
Substituting into the equation:
5.31x10^(-9) = 8.854x10^(-12) * A / 5x10^(-3)
A = 3.00 m^2
Which sentence describes an object that has gravitational potential energy?
Select one:
a.
A beach ball is round.
b.
A radio has batteries with stored chemical energy.
c.
A seagull sits on top of a fence post.
d.
A boat sails across the ocean.
Answer:
C. A seagull sits on top of a fence post.
What force causes raindrops to fall to Earth?
A.lift
B.drag
C.gravity
D.buoyancy
Answer:
Gravity
Explanation:
Because gravity try to pull everything toward the earth center. So raindrops fall towards the ground
A hummingbird beats its wings 80 times in 4 seconds. What is its period? (answer as a decimal, not a fraction.
What is the hummingbird's wingbeat frequency?
Answer:
20 per second
Explanation:
80/4
20
The hummingbird beats its wing 20 times per second!
Have an amazing day!!
PLEASE RATE AND MARK BRAINLIEST!!
A small sphere with a charge of 4 nC is brought close to but does not touch uncharged conducting sphere A, which is grounded. The ground is disconnected, and the small sphere is removed. Sphere A is then brought close to but does not touch uncharged conducting sphere B. What is the net charge on sphere B as a result, and what is an explanation for the charge
Answer:
the answer is b that's my answer
Can an object have both potential and kinetic energy at the same time ?
Answer:
yes
Explanation:
An object can be elevated and moving at the same time, example: a thrown ball
Explanation:
Ofcourse! Objects can have both kinetic energy and potential energy at the same time.
An object can be elevated above the ground (have potential energy) and be moving at the same time (and also have kinetic energy).8. A 55-kg skateboarder enters a ramp moving horizontally with a speed of 6.5 m/s, and leaves the ramp moving vertically with a speed of 4.1 m/s. (A) Find the height of the ramp, assuming no energy loss to frictional forces. (B) What is the skateboarder's maximum height above the bottom of the ramp?
(a) The energy lost to friction by the skateboarder is -699.6 J.
(b) The maximum height above the bottom of the ramp is 1.3 m.
Energy loss to frictionThe energy lost to friction by the skateboarder is calculated from the change in kinetic energy of the skateboarder.
ΔK.E = K.Ef - K.Ei
ΔK.E = ¹/₂m(vi² - vf²)
ΔK.E = 0.5 x 55 (4.1² - 6.5²)
ΔK.E = -699.6 J
Maximum height above the bottom of the rampThe maximum height above the bottom of the ramp is determined from conservation of energy.
mghi + ¹/₂mvi² = ¹/₂mvf² + mghf
55 x 9.8 x hi + (0.5 x 55 x 6.5²) = (0.5 x 55 x 4.1²) + (55 x 9.8 x 0)
539hi + 1161.88 = 462.28
539hi = -699.6
hi = -699.6/539
hi = -1.3 m
Thus, the maximum height above the bottom of the ramp is 1.3 m.
Learn more about conservation of energy here: https://brainly.com/question/166559