earth's atmosphere is approximately 78% nitrogen and 21% oxygen. what is the mass in grams of oxygen in a cubic meter of air in a typical classroom at 1 atm and 25C (1m^3=1000L)

Answer:

c. they have the same number of valence electrons

Answer:

I would go with

B. Surface water at the poles is dense because of low temperatures and high salinity.

i could be wrong tho.

Explanation:

Answer:

Li: 2

H2O: 2

LiOH: 2

H2: 1

Explanation:

Good luck

Answer:

9.16895 grams

Explanation:

cuz u have number of moles of silver which = 0.085

so u must know that molar mass of silver =107.87 g/mol

so the mass of silver = number of moles × molar mass =0.085×107.87= 9.16895 grams

Explanation:

[tex] \frac{p1v1}{t1} = \frac{p2v2}{t2} [/tex]

1 × 30/273 = 2 × V2/300

V2=300×30/2×273

V2= 16.5 ml

Answer:

4

Explanation:

2+2=4

Moles be n

[tex]\\ \rm\Rrightarrow PV=nRT[/tex]

[tex]\\ \rm\Rrightarrow n=\dfrac{PV}{RT}[/tex]

[tex]\\ \rm\Rrightarrow n=\dfrac{1.28(27.6)}{0.0821(302)}[/tex]

[tex]\\ \rm\Rrightarrow n=\dfrac{35.3}{24.8}[/tex]

[tex]\\ \rm\Rrightarrow n=1.42mol[/tex]

The number of moles of methane gas occupies in the given volume and pressure is 1.426 moles. It can be calculated using ideal gas law.

Ideal gas law relates the parameters temperature, pressure, volume and number of moles of  a gas by the equation given below:

PV = nRT.

Where, R is the universal gas constant equal to 0.082 L atm /(K .mol). This law is a combination of Boyle's law, Charles's law and Avogadro's law.

It is given that the pressure and volume of the gas is 1.28 atm and 27.6 liter respectively. Temperature is 29 degree celsius or 302 kelvin. Using these values the number of moles of methane gas is calculated as follows:

PV = nRT

n = PV/RT

Number of moles of methane n = (1.28 atm × 27.6 L) / ( 0.082 L atm /(K .mol) × 302 K )

= 1.426 moles.

Hence, the number of moles of methane gas in the given system is 1.426 moles.

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Answer:

0.52 mole

Explanation:

How many moles of Al2O3 will be formed when 27 grams of Al reacts with O2? Hence 0.78 mole of oygen react with Aluminium to give 0.52 mole of Al2O3.

it has to be b

Explanation:

bc the 4th power to 5 is 2

Answer:

recognition, intrusion and distraction

Explanation:

Answer:

The propane chemical structure, or chemical formula, is three carbon atoms branched with eight hydrogen atoms I.e C3H8

The energy of -91.8 kJ in the reaction equation shows that energy is released so this is an exothermic reaction.

A thermochemical equation is one which just does not only show the reactants and products but also shows the energy absorbed or emitted in the reaction.

We can see from the thermochemical equation; N2(g) + 3H2(g) → 2NH3(g); ΔH = -91.8 kJ that the negative enthalpy implies that  energy is released so this is an exothermic reaction.

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Answer:

The wind will keep pushing against it and it will go around and above it. You can test this by holding a pot and a hairdryer. The air will go around the pot so the wind will do the same. The wind will go aound the object blocking its path by going to the side or up.

Explanation:

The wind will keep pushing against it and it will go around and above it. You can test this by holding a pot and a hairdryer. The air will go around the pot so the wind will do the same. The wind will go aound the object blocking its path by going to the side or up.

THEY ARE CALLED PREVAILING WINDS!!!!

Have an amazing day!!!

PLEASE RATE AND MARK BRAINLIEST!!!!

Answer: 1. D. It warms the air masses.

2. D. The air moves from high to low pressure systems.

3. B. It is pushed upwards and out.

4. B. uneven rainfall

Hope this helped! Brainliest would be appreciated. :)

Answer:

3

Explanation:

That's the answer

I hope it helps

Answer:

illustrates ways things are similar and different

Explanation:

Answer:

illustrates ways things are similar and different

The concentration of the solution reduces and the number of moles of solute isn't affected.

Data;

1. When the solution is diluted, the concentration changes and this time, the concentration reduces.

Using dilution formula

[tex]c_1 v_1 = c_2 v_2\\12 * 50 = c_2 * 200\\c_2 = \frac{600}{200} \\c_2 = 3M[/tex]

The concentration of the solution reduces.

2. The number of moles remains the same.

When a solution is diluted, the number of moles remains the same because there's no change in the mass of the solute.

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Answer:

B. Because the planet travels slowly when it is far away from the sun

Answer: A

Explanation:

Based on the concentration of the solutions, the increase in volume is as follows:

Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.

The movement of water molecules in the solution pairs is as follows:

Therefore, the increase in volume depends on the concentration ofvthe solutions.

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Answer:

Decision making

Explanation:

A person who thinks before choosing is a person who makes decisions.

Answer:

The mass of 1 mole LiOH has been 24 g. Thus, option D is correct.

The mass of a compound present in a mole of sample has been equivalent to the molar mass of the compound. The molar mass of the compound has been the sum of the constituent in a formula unit.

Explanation:

pls mark brainless i mean brainliest!

Answer: 24 g

Explanation:

[tex]\Large \text{1)}[/tex]

[tex]\textbf{Use the formula and substitute the values}[/tex]

[tex]\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}[/tex]

[tex]\textbf{Solve for the number of moles}[/tex]

[tex]n = 0.003\ mol[/tex]

[tex]\textbf{Calculate final volume }[/tex]

[tex]40+10=50\ mL[/tex]

[tex]\textbf{Number of moles remains same. Solve for concentration}[/tex]

[tex]\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L[/tex]

[tex]\Large \text{2)}[/tex]

[tex]\displaystyle DF=\frac{V_f}{V_i}[/tex]

[tex]\displaystyle DF=\frac{50}{10}=5[/tex]

Answer:The colour and distribution of the organism's biochromes

Explanation:

The colour and distribution of the organism's biochromes (pigments), particularly the relative location of differently coloured areas; the shape, posture, position, and movement of the organism; and the quality and quantity of light striking the organism

Answer:

Because chemists need to think outside the box for what they do, in other words, "science is not always black and white" which means science has color to it or many different aspects some of those which are not yet discovered and needs critical thinking chemists to figure out and discover.

Explanation:

(this was all in my own words and not actually cut and Paiste ○|￣|_ =3)

The volume of the balloon is approximately 2652 liters.

Let suppose that flammable hydrogen behaves ideally. GIven the molar mass ([tex]M[/tex]), in kilograms per kilomole, and mass of the gas ([tex]m[/tex]), in kilograms. The volume occupied by the gas ([tex]V[/tex]), in cubic centimeters, is found by the equation of state for ideal gases:

[tex]V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}[/tex]   (1)

Where:

If we know that [tex]m = 0.239\,kg[/tex], [tex]R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}[/tex], [tex]T = 273.15\,K[/tex], [tex]P = 101.325\,kPa[/tex] and [tex]M = 2.02\,\frac{kg}{kmol}[/tex], then the volume of the balloon is:

[tex]V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}[/tex]

[tex]V = 2.652\,m^{3}[/tex] ([tex]2652\,L[/tex])

The volume of the balloon is approximately 2652 liters. [tex]\blacksquare[/tex]

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Answer:

Explanation:

1. There are fire and flashes at the top of an active volcano. No fire nor flashes for inactive volcano.

2. Smoke and debris come off an active volcano. No smoke nor debris from inactive volcano.

3. Magma flows from top of active volcano. No magma from inactive volcano.

4. There can be snow on top of inactive volcano. Active volcano is too hot for that.

5. There are plants and other wild lives around an inactive volcano.

Answer:

H

2

O

2

(aq)+ClO

4

−

(aq)⟶O

2

(g)+ClO

2

−

(aq)

All atoms except H and O are balanced.

The oxidation number of Cl changes from 7 to 3. The change in the oxidation number is 4.

The oxidation number of O changes from -1 to 0. The change in oxidation number per O atom is 1.

Total change in the oxidation number for 2 oxygen atoms is 2.

To balance the increase in oxidation number with decrease in the oxidation number, multiply H

2

O

2

and O

2

with coefficients 2.

2H

2

O

2

(aq)+ClO

4

−

(aq)⟶2O

2

(g)+ClO

2

−

(aq)

To balance O atoms, add 2 water molecules on RHS.

2H

2

O

2

(aq)+ClO

4

−

(aq)⟶2O

2

(g)+ClO

2

−

(aq)+2H

2

O(l)

The oxygen atoms are already balanced.

This is the balanced chemical equation