Find the velocity of the watch whose radius is 5 meter and time is 2 seconds​

Answers

Answer 1

Question :-

Find the Velocity of the Watch whose Radius is 5 meter and Time is 2 seconds .

Answer :-

Velocity of the Watch is 2.5 m/s .

[tex] \rule {180pt} {2pt} [/tex]

Given :-

Radius = 5 meterTime = 2 seconds

To Find :-

Velocity = ?

Solution :-

As per the provided information in the given question, we have been given that the Radius of the Watch is 5 meter , Time is given 2 seconds . And, we have been asked to calculate the Velocity of the Watch .

For calculating the Velocity , we will use Formula :-

Velocity = Displacement / Time

Therefore , by Substituting the given values in the above Formula :-

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5

Hence :-

Velocity = 2.5 m/s .

[tex] \underline {\rule {180pt} {4pt}} [/tex]

Answer 2

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5


Related Questions

50 points if you want it

Answers

Answer:

Angular momentum increases and gravitational potential energy decreases after the bug lands.

Explanation:

After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.

As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.

The question has been asked and answered before: please see the following for previous answers.

brainly.com/question/21305995

50 points, absurd answers will be reported if there are no answer content

Answers

Answer:

Angular momentum increases and gravitational potential energy decreases after the bug lands.

Explanation:

After the bug lands, the rod begins to rotate. As the system was at rest before, when it begins to rotate, its angular momentum increases from zero to positive.

As the rod begins to rotate, the heavier mass of bug and sphere goes down while the lighter mass of sphere goes up. So the system's gravitational potential energy decreases.

The question has been asked and answered before: please see the following for previous answers.

https://brainly.com/question/21305995

Rock candy is made from crystallized sugar. What is crystallization?

Answers

Answer: Rock candy is candy made of large sugar crystals. To make rock candy, a supersaturated solution of sugar in water is created and left undisturbed for a few days. The driving force behind crystallization is supersaturation.

A crate is released from the highest point of a 12 m long ramp inclined at 60° with the horizontal. The motion is frictionless. What is the speed of the crate at the base of the ramp?​

Answers

law of conservation of mechanical energy

PE1 = Ek2

mgh=1/2mv²

h = 12 sin 60

[tex]\tt v=\sqrt{2gh}=\sqrt{2\times 9.8\times 12\times sin~60}=14.27~m/s[/tex]

HELP PLEASE Which of the following is a true statement?

All organisms in an ecosystem eat decomposers to survive.
All organisms in an ecosystem eat decomposers to survive.

All organisms rely on photosynthesis, which is done by decomposers.
All organisms rely on photosynthesis, which is done by decomposers.

All organisms generate waste and dead material that is recycled by decomposers.
All organisms generate waste and dead material that is recycled by decomposers.

All organisms are considered decomposers in aquatic ecosystems since all organisms are underwater.

Answers

Answer: All organisms generate waste and dead material that is recycled by decomposers.

Explanation: Give me brainiest!



A force of 345 N is applied to a 70 kg scooter. What will the scooter's
acceleration be?

Answers

Explanation:

here, force applied (N) = 345 N

or, mass of scooter (m) = 70 kg

now, acceleration (a) = ?

we know, force = mass × acceleration

or, 345 = 70 × acceleration

or, acceleration = 345/70

therefore, acceleration = 4.9 m/s2 (meter/second square)

Energy cannot be changed from one variety to another.
True or False

Answers

Answer:

False, Hope this helps.

PLEASE HELP ME !! STUCK ON THIS!
Which choice describes the purpose of the blades in a wind turbine?

A) The blades convert wind energy into rotational energy.

B) The blades include a gearbox and a generator.

C) The blades create charges inside an electromagnet.

D) The blades provide structural support to the turbine.

Answers

Answer:

A is the basis for all of the other assumptions.

Everything else supports A.

Answer:

A) The blades convert wind energy into rotational energy.

Explanation:

Wind turbines use blades to collect the wind's kinetic energy. Wind flows over the blades creating lift (similar to the effect on airplane wings), which causes the blades to turn. The blades are connected to a drive shaft that turns an electric generator, which produces (generates) electricity.

When studying energy, the main units to consider are the calories. However, many times the needed numbers are not readily available. Often, conversions need to be done in order to calculate the correct values. Knowledge of the metric system is essential to do this successfully.

If a female lion runs a distance of 469.2 meters while chasing an antelope, how many millimeters did she run?
A.
0.0004692 mm
B.
0.4692 mm
C.
46,920 mm
D.
469,200 mm

Answers

Answer:

B. O.4692 mm

Explanation:

I hope its help keep safe

Answer:

Its  D trust me it is

Explanation:

effect of earthquake Causes of earthquake and protection against earthquake. final conclusion​

Answers

Causes of earthquake:

1 Groundwater extraction – decrease in pore pressure

2. Groundwater – increase in pore pressure.

3. Heavy rain.

4. Pore fluid flow.

5. High CO2 pressure.

6. Building dams.

Effects of earthquake:

1. Loss of lives

2. Increase in government expenditure

3. Loss of properties

Protection against earthquake:

We cannot prevent natural earthquakes from occurring but we can significantly mitigate their effects by identifying hazards, building safer structures, and providing education on earthquake safety. By preparing for natural earthquakes we can also reduce the risk from human induced earthquakes.

you have two positively charged spheres. one sphere has 3 times the charge of the other sphere if they are 0.16m apart and the force between them is 0.28 N, what are the charges of the two spheres?

Answers

this is the answer

pls give brainliest

In a two-cell flashlight the batteries are normally connected in series. Why not connected them in a parallel.​

Answers

Answer:

In series the battery voltage adds up but in parrel they don't which makes is usefull for a small device which uses multiple batteries.

(if this is correct pls mark this brainly to let me know ty :)

3. Which of the following are true of static electricity charges? *
+
A positively charged object has lost electrons.
A positively charged object has gained protons.
A positively charged object has gained electrons

Answers

A positively charged object has lost electrons
A positively charged object has lost electrons.

Two insulating materials have rubbed together. One material transfers negative electrons to the other.

The one that transfers and thus loses the electrons becomes positively charged and the one that gains these electrons becomes negatively charged.

So a positively charged object has lose electrons.

Can’t be the second option because protons cannot move and so aren’t transferred.

A car starts from rest and reaches a speed of 14/s in 10 s Its acceleration is what?

Answers

Answer:

acceleration = change in velocity / change in time

acceleration = 14/10

acceleration = 1.4/s^2

A circular metal disc is heated. Which quantity decreases?

Answers

Answer:

Bbbbb. Metal disc.

Explanation:

Sent from my Huawei and I am not a good person and I am not a good person and I am not a good person and I am not a good person

A 10 g piece of sticky clay moving horizontally with a speed of 12 m/s strikes a pendulum bob and sticks to the bob. The pendulum bob has a mass of 50 g and it is suspended from a 0.7 m string.

a. Find the momentum of the clay before the collision.

b. *Find the momentum of the clay-bob system after the collision.

c.*Find the velocity of the clay-bob system after the collision.

d. *Find the kinetic energy of the clay-bob system after the collision.

e. *Find the maximum height of the clay-bob system that they deflect after the collision.

f. *What velocity should the clay have before the collision in order for the clay-bob system to complete one circle?​

Answers

Answer:

it is d that my answer to the question

a. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

What is momentum?

Momentum is the product of mass and velocity

It is given by ,

p= mv

where, p = momentum

m = mass

v = velocity

What is velocity?

velocity is the rate of change of displacement.

To solve , we use Law of conservation of momentum and Law of conservation of  mechanical energy

What is Law of conservation of momentum?

Law of conservation of momentum states that  in absence of any external forces , the momentum of a system always remains conserved.

i.e,

The momentum  of the system before collision = momentum of the system after collision.

[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]

Where,

m₁ = mass of first body.

m₂ = mass of the second body.

u₁ = velocity of first body before collision,

u₂ = velocity of the second body before collision

v₁ = velocity of first body after collision

v₂ = velocity of first body after collision.

v₂ = velocity of second body after collision.

What is law of conservation of mechanical energy

The Law states that the total mechanical energy of a system remains conserved and energy can be converted from one form to another form.

The sum of kinetic energy an potential energy is equal to total mechanical energy which is a constant.

So, K.E + P.E = constant

a, Here mass of clay m₁ = 10g = 0.01kg,

velocity of the clay = 12m/s.

therefore, momentum  p = mv.

p = 0.01 x 12 = 0.12kg m/s.

Hence momentum of clay is 0-12kg m/s.

b. The momentum of clay - bob system after collision is

From law of conservation of momentum ,

final momentum = initial momentum

since initial momentum  = 0.12kg m/s

therefore momentum of the clay-bob system after collision is 0.12kg m/s

c. To find the velocity of the body we apply law of conservation of momentum

[tex]m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}[/tex]

Here  m₁u₁ = 0.12kgm/s

m₂u₂ = 0 (since bob is at rest initally)

m₁ = 10g = 0.01kg

m₂ =  50g = 0.05kg

after collision the system moves with a common velocity v

So,

m₁u₁ = (m₁ + m₂)v

0.12 = (0.01 + 0.05 ) v

So, v = 0.12/0.06 = 2m/s

Hence velocity of clay -bob system after collision is = 2m/s.

d. The kinetic energy of the clay-bob system after the collision.

kinetic energy = 1/2 mv²

Here. m = 0.06kg

v = 2m/s

therefore K.E = (1/2)x 0.06 x 2²

K.E = 0.12J

Hence Kinetic energy of the clay-bob system after collision is 0.12J

e. The maximum height of the clay-bob system that they deflect after the collision.

From Law of Conservation of mechanical energy we have,

The kinetic energy = The potential energy

so, 1/2 mv² = mgh

Here, m = 0.06kg

g= 9,8m/s²

h = height.

So,  h =  2/9.8 = 0.204m

Hence height to which the clay-bob system will rise after collision is 0.204m

e.  To find the velocity that clay should possess  before collision in order for the clay- bob   system to gain the velocity so that it completes the circle -

The velocity that the particle should have at the bottom of the circle in order to complete the circle is v = [tex]\sqrt{5rg\\}[/tex]

Where, r = radius of the circle

g = acceleration due to gravity

Here,

r = 0.7m

g = 9.8m/s

So, v = [tex]\sqrt{5 X0.7 X 9.8 }[/tex] = 5.85m

So clay-bob system should have a velocity of 5.85m at the bottom of the circle so that it can complete the circle

Now,  applying Law of conservation of momentum

m₁u₁ = (m₁ + m₂)v

Here, m₁ = 0.01kg

m₂ = 0.05kg

v = 5.85m/s

So, 0.01u₁ = 0.06 x 5.85  

Hence u₁ = 35.13m/s

So velocity that clay should have is 35.13m/s.

Therefore  the solution of the question is

. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

To know more on momentum here

https://brainly.com/question/24030570

#SPJ2

An object, initially at rest, accelerates uniformly with an acceleration of 6 m/s². What is the displacement of the object after 10 s?
a. 300m
b. -300m
c. 600 m
d. -600m

Answers

The answer is a 300m

A solid steel ball is thrown directly downward, with an initial speed 7.30 m/s, from the top of a building at a height of 29.5 m. How much time in seconds does it take before the ground?

Answers

Answer:

1.82 seconds

Explanation:

see paper for full explanation :)

h=vi.t+1/2gt²

29.5 = 7.3t+1/2 x 9.8 x t²

4.9t²+7.3t-29.5=0

abc formula⇒ t = 1.82 s

Forest protect the soil from erosion ? True or False

Answers

Answer:

True

Forests helps in binding the soil together. Thus, prevent soil from erosion.

Answer:

True

Explanation:

Forest protect the soil from erosion because the trees in the forest hold the soil together not allowing it to erode.

Please answer this question. Thank you and have a fruitful day.

Answers

Answer:

top box: upthrust

right box: water resistance

bottom box:gravity / weight

left box: thrust

Explanation:

You too have a fruitful day! Hope I could help!

#Down

The weight of the ship is pulling downwards

#Up

Upthrust or buyoant force of water

#Left

The force of motor

#Right

Drag force of air

Express 900 rev/hour (rpm) in rad/s

Answers

Answer:

900 Revolution/Minute (rev/min)

=

94.24778 Radian/Second (rad/s)

Explanation:

A 0.37 kg rock is thrown vertically upward from the top of a 37 m
cliff. When it hits the ground at the base of the cliff, the rock has a
speed of 33 m/s. Consider that air resistance is negligible. Use
conservation of total mechanical energy principle to find

a. The initial speed of the rock.
b. The greatest height of the rock as measured from the base of the
cliff.
c. Comment on the types of mechanical energy of the rock when
i) it is thrown upward, ii) it reached the maximum height, and
iii) it reached the base of the cliff.

Answers

(a) The initial speed of the rock is 19.1 m/s.

(b) The greatest height of the rock as measured from the base of the

cliff is 55.6 m.

(c) i. As the ball is thrown up, its kinetic energy is converted to potential energy.

ii. When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.

iii. When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.

Conservation of mechanical energy

The initial speed of the rock is determined by applying the principle of conservation of mechanical energy as shown below;

Ui + K.Ei = Uf + K.Ef

mghi + ¹/₂mvi² = mghf + ¹/₂mvf²

(0.37 x 9.8 x 37) + ¹/₂(0.37)vi² = (0.37 x 9.8 x 0) + ¹/₂(0.37 x 33)²

134.16 + 0.185vi² = 0 + 201.47

0.185vi² = 201.47 - 134.16

0.185vi² =  67.31

vi² = 67.31/0.185

vi² = 363.84

vi = √363.84

vi = 19.1 m/s

Height reached by the rock from top cliff

vf² = vi² - 2gh

0 = vi² - 2gh

2gh = vi²

h = vi²/2g

h = (19.1)²/(2 x 9.8)

h = 18.6 m

Maximum height reached by rock from the base of the cliff

The maximum height from the base = 37 m + 18.6 m = 55.6 m

When the ball is thrown up, its kinetic energy is converted to potential energy.

When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.

When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.

Learn more about conservation of mechanical energy here: https://brainly.com/question/6852965

a An electron is placed in a uniform electric field with field strength of 150lavono calculate the duration fort to travel somm from its stationary position. Give an Explanation for your Answer.​

Answers

Explanation:

Explanation for your Answer.

A 5.0 kg book is lying on a 0.25 meter high table.
You pick it up and place itn on a bookshelf 1.85 m above the floor.
During this process:
a.) How much work does your hand do on the book? J
(round to the nearest full joule)

Answers

Answer:

Below in the picture:-

I hope it helps.

The figure is a cross section through three long wires with linear mass density 55.0 g/m. They each carry equal currents in the directions shown. The lower two wires are 4.0 cm apart and are attached to a table. (Figure 1)

Answers

The current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.

Net force at the center of the equilateral triangle

The current that will allow the upper to float will form zero resultant force due to the current at the left and the current at the right.

Weight effect of the wires acting downwards

W =  mg

W = (σL)g

Resultant electric force of the two upward wires

[tex]F_1 = F_2 = \frac{\mu_o I^2 l}{2\pi r}[/tex]

The total force due to angle formed by the top wire

[tex]F_t = F_1cos\theta + F_2 cos \theta= 2Fcos\theta = \frac{2\mu_o I^2 l \times cos\theta}{2\pi r} \\\\F_t = \frac{\mu_o I^2 l \times cos\theta}{\pi r}[/tex]

At equilibrium the upward force must equal downward force

[tex]\sigma lg=\frac{\mu_o I^2 l \times cos\theta}{\pi r}\\\\I^2 = \frac{\sigma lg \pi r}{\mu_0 l \times cos\theta} = \frac{\sigma g \pi r}{\mu_0 \times cos\theta} \\\\I^2 = \frac{(0.055)\times 9.8\pi \times 0.04 }{4\pi \times 10^{-7} \times cos60} \\\\I^2 = 107,800\\\\I = \sqrt{ 107,800} \\\\I = 328.3 \ A[/tex]

Thus, the current that will allow the upper wire to float so as to form an equilateral triangle with the lower wires is 328.3 A.

Complete question is below:

The figure is a cross section through three long wires with linear mass density 55.0 g/m. They each carry equal currents in the directions shown. The lower two wires are 4.0 cm apart and are attached to a table. (Figure 1). What current I will allow the upper wire to "float" so as to form an equilateral triangle with the lower wires?

Learn more about magnetic force here: https://brainly.com/question/13277365

In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Select all that apply.

There is no change in the kinetic energy of the book.

The potential energy of the book-Earth system decreases.

The potential energy of the book-Earth system increases.

The potential energy of the book increases.

Answers

Answer:

There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Explanation:

This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Learn more about kinetic energy: https://brainly.com/question/15308590

the teacher uses the ____ theorem to solve the equation.
A) mass-acceleration
B) work-energy

Answers

Answer:

B) work-energy

Explanation:

It is the work-energy theorem as there is no theorem called "mass-acceleration theorem" [unless you consider Newton's Second Law (maybe?) but not really].

Its postulates are :

Work done by all the forces = Change in Kinetic Energy. W g + W N + W f =K f – K i Where W g = work done by gravity W N = work done by a normal forceW f = work done by frictionK f = final kinetic energy.

A Wave with a Frequency of 500 Hz is travelling at Speed of 200 m^-1 . What is its Wavelength ?​

Answers

Question :-

A Wave with a Frequency of 500 Hz is travelling at Speed of [tex] \bf {200 \: m ^{-1}} [/tex] . What is its Wavelength ?

Answer :-

Wavelength of the Wave is 0.4 m .

[tex] \rule {180pt} {2pt} [/tex]

Given :-

Frequency = 500 HzSpeed = [tex] \bf {200 \: m ^{-1}} [/tex]

To Find :-

Wavelength = ?

Solution :-

As per the provided information in the given question, we have been given that the Frequency of the Wave is 500 Hz . Its Speed is given [tex] \bf {200 \: m ^{-1}} [/tex] . And, we have been asked to calculate the Wavelength .

For calculating the Wavelength , we will use the Formula :-

Wavelength = Speed / Frequency

Therefore , by Substituting the given values in the above Formula :-

⇒ Wavelength = 200 / 500

⇒ Wavelength = 2 / 5

⇒ Wavelength = 0.4

Hence :-

Wavelength = 0.4 m

[tex] \underline {\rule {180pt} {4pt}} [/tex]

What is the current in a 160 V circuit if the resistance is 2

Answers

V= IR

160 = I × 2

80 A = I = current

Answer:

80 A

Explanation:

by ohm's law, resistance is equal to the change in voltage over the current so if we plug and solve for current we get I = (160V)/(2V/A)= 80 A

An ice skater can change the rate of their spin by moving their arms into and away from their body without any other forces or torques. Explain this in terms of angular momentum.

Answers

Answer:

Angular momentum is conserved if there are no external forces

P1 = P2

I1 ω1 = I2 ω2

ω2 / ω1 = I1 / I2

If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.

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