Gas mileage is the number of miles you can drive on a gallon of gasoline. A test of a new car results in 510 miles on 20 gallons of gas. How far could you drive on 65 gallons of gas?

Answers

Answer 1

Answer:

The answer is 1,657.5 miles

Step-by-step explanation:

First divide 510 by 20 510 ÷ 20 = 25.5 into 65 = 1657.5

Answer 2

Given that test of a new car results in 510 miles on 20 gallons of gas. By unitary method, you can drive miles on 65 gallons of gas.

Unitary method is a method of solving a problem wherein to find the value of k units, you first calculate the value of one item, then multiply the value of the one item to k.

Given in the question,

distance covered in 20 gallons of gas  = 510 miles

distance covered in 1 gallons of gas  = [tex]\frac{510}{20} = 25.5[/tex] miles

distance covered in 65 gallons of gas = 25.5 * 65 miles = 1657.5 miles

Learn more about unitary method here

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Related Questions

100 points!!!! Whatbis the simplest form of x4y7/3√x10y4

Answers

Answer:

The last one.

Step-by-step explanation:

Answer:

y^5 cubed root x^2 y^2

Step-by-step explanation:

edge 2023

An ad says that 6 lemons cost $1.86. What will 8 lemons cost?

Answers

Answer:  2.48

Step-by-step explanation:

We have the ad that shows:

6 lemons for .....................1.86 dollars

8 lemons..............................?

the cost for 8 lemons= (8*1.86)/6=2.48

of course we can use another method,

1.86/6=0.31 cents for 1 lemon

8*0.31=2.48 and we get the same answer

Answer:

$2.48

Step-by-step explanation:

1.86/6=0.31 which is the cost for 1 lemon. 0.31*8=2.48 which is for 8 lemons.

Which expression results when the change of base formula is applied to log subscript 4 baseline (x 2)? startfraction log (x 2) over log 4 endfraction startfraction log 4 over log (x 2) endfraction startfraction log 4 over log x 2 endfraction startfraction log x 2 over log 4 endfraction

Answers

When the change of base formula is applied to log subscript 4 baseline (x+2), the result is [tex]\dfrac{log(x+2)}{log4}[/tex].

What are the Properties of logarithms?

There are four basic properties of logarithms:

[tex]\rm log_aU+ log_aV = log_a(UV)\\\\log_aU - log_aV = log_a(\dfrac{U}{V})\\\\log_aU^n = n\ log_aU\\\\\log_ab = \dfrac{log_xb}{log_xa}\\\\[/tex]

When the change of base formula is applied to log subscript 4 baseline (x 2), the result expression will be,

[tex]\rm log_4(x+2)=\dfrac{log_{10}(x+2)}{log_{10}4}=\dfrac{log(x+2)}{log4}[/tex]

Hence, when the change of base formula is applied to log subscript 4 baseline (x+2), the result is [tex]\dfrac{log(x+2)}{log4}[/tex].

Learn more about Logarithms:

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Answer:

a - StartFraction log (x + 2) Over log 4 EndFraction

Step-by-step explanation:

edge 2022

If you you give sally 26 apple and take 13 apples away. How much apples would Sally have left? PLS HELP!!!!!!!!!

Answers

Answer:

she'd have 13 left hope this helps:)

Graph the function. Then identify the domain and range of the function.
f(x)=3/8x^2

Answers

Answer:

Step-by-step explanation:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(−∞,∞)

Set-Builder Notation:

{x|x∈R}

The range is the set of all valid y

values. Use the graph to find the range.

Interval Notation:

[0,∞)

Set-Builder Notation:

{y|y≥0}

Determine the domain and range.

Domain: (−∞,∞),{x|x∈R}

Range: [0,∞),{y|y≥0}

please help (AP Calc AB) will mark brainliest! image provided

Answers

Answer:

So I think your answer is Zero

I think it will help you.

Tell whether (-4, 3) is a solution of the system of linear inequalities.

Answers

Answer:  No, it is not a solution

Explanation:

Refer to the diagram below. The point (-4,3) marked in red is outside the blue shaded region. So it doesn't make both inequalities true, and therefore not considered a solution.

In contrast, a point like (-5,1) is a solution as it is in the shaded region.

Put another way, the set of all solution points must be below both the solid line and the dashed line. Points can be on the solid line, but must be adjacent to the blue shaded region. The fact (-4,3) is on the solid line doesn't count because its not below the dashed line.

PLEASE EXPLAIN HOW TO DO THIS

Answers

The volume of any rectangular prism is length*width*height.

Based on the diagram:
length: 9km
width: 9km
height: 3km

9*9*3=243 km^3 (aka answer choice B)

Classify/name the shape based on the number of sides and markings.
Hint: Two Words

Answers

I believe this is an equilateral octagon. There are eight sides and they all have a dash, indicating equality. Hope this is helpful and accurate! :)
They are right it is an equilateral octagon

If y varies directly w x and y = -12 when x = 6 find x when y = -4

Answers

-12 = -2 times 6. So the formula is y = (-2 times x) to find x. So, y= -4,

-4 = -2 times 2. So the answer is 2.

Which is the most efficient method substitution or elimination or graphing to solve the system of equation. Explain why the method you pick is the is the most efficient. 5x + 3y = 6 and -4x -3y = -3

Answers

Answer:

see explanation

Step-by-step explanation:

5x + 3y = 6 → (1)

- 4x - 3y = - 3 → (2)

the most efficient method here would be elimination.

add (1) and (2) term by term to eliminate y

x + 0 = 3

x = 3

substitute x = 3 into either of the 2 equations and solve for y

substituting into (1)

5(3) + 3y = 6

15 + 3y = 6 ( subtract 15 from both sides )

3y = - 9 ( divide both sides by 3 )

y = - 3

solution is (3, - 3 )

Answer:

[tex](3,-3)[/tex]

Step-by-step explanation:

[tex]5x + 3y = 6[/tex]

The most efficient method for this equation is elimination.

[tex]x + 0 = 3[/tex]

[tex]5(3) + 3y = 6[/tex]

Substitute x = 3 into any of the equation and solve for y.

[tex]5(3) + 3y = 6[/tex]

[tex]15 + 3y = 6[/tex]

[tex]-15 -15[/tex]

[tex]3y = - 9[/tex]

[tex]\frac{3y}{3}=\frac{-9}{3}[/tex]

[tex]y=-3[/tex]

[tex](3,-3)[/tex]

PLS HELP ME WITH THIS

You spend half of your allowance on Monday.
On Tuesday, you spend half of what is left.
Then on Wednesday, you spend half of what remains.

What fraction of your allowance do you have left? Choose the most reasonable answer.

Answers

Answer:

Assuming you want to know what fraction of the original amount you have.

a = allowance

(1/2)a = what have left after Monday

(1/2(1/2)a = what you have after Tuesday

(1/2)(1/2)(1/2)a = what you have after Wednesday.

Doing the multiplication.

(1/8)a = what you have left.

You have 1/8 of what you had at the start.

Hope this help u

Answer:

1/8 i think

Step-by-step explanation:

The formula below gives the monthly payment m needed to pay off a loan of P dollars atr
percent annual interest over N months, Which of the following gives P in terms of m, r, and N?

Answers

Answer:

This day is going to be perfect

The kind of day of which I dreamed since I was small

Everypony will gather round

Say I look lovely in my gown

What they don't know is that I have fooled them all

Step-by-step explanation:

let a and b be the roots of the equation x^2-2(p+1)x+p^2+8=0. If the absolute value of the difference of a and b equals to 2. find p

Answers

Answer:

4

Step-by-step explanation:

a and B are the roots of

[tex] {x}^{2} - 2(p + 1)x + {p}^{2} + 8 = 0[/tex]

[tex] {x}^{2} - 2px - 2x + {p}^{2} + 8 = 0[/tex]

This look like a parabola since p will be a constant so let use a quadratic formula

[tex] {x}^{2} -(2p + 2)x + {p}^{2} + 8 = 0[/tex]

[tex]2p + 2± \frac{ \sqrt{4 {p}^{2} + 8p + 4 - (4 {p}^{2} + 32) } }{2} [/tex]

[tex]2p + 2± \frac{ \sqrt{8p - 28} }{2} [/tex]

[tex]2p + 2± \frac{2 \sqrt{2p - 7} }{2} [/tex]

[tex]2p + 2± \sqrt{2p - 7} [/tex]

So the roots are

[tex]2p + 2 + \sqrt{2p - 7} [/tex]

and

[tex]2p + 2 - \sqrt{2p - 7} [/tex]

We know the distance between these two points are

2 so

[tex] |(2p + 2) + \sqrt{2p - 7} - (2p + 2) - \sqrt{2p - 7} | = 2[/tex]

[tex] | \sqrt{2p - 7} + \sqrt{2p - 7} | = 2[/tex]

[tex] |2 \sqrt{2p - 7} | = 2[/tex]

[tex]2 \sqrt{2p - 7} = 2[/tex]

[tex]p = 4[/tex]

Let plug it in to see.

[tex] {x }^{2} - 2(4 + 1)x + {4}^{2} + 8 = 0[/tex]

[tex] {x}^{2} - 10x + 24 = 0[/tex]

[tex](x - 6)(x - 4) = 0[/tex]

[tex]x = 4[/tex]

[tex]x = 6[/tex]

So they have a distance of 2.

List the potential solutions to 2 ln x = 4 ln 2 from least to greatest. X = and x =.

Answers

Is there a picture to show

Answer:

x=-4 and x=4

Step-by-step explanation:

solution to equation is 4

Need help on this question ASAP pleasee and thanks!

Answers

Answer:

Sorry but I don't know the answer too this question

Solve: 4 In x=2 In 25
Ox=5
O x = 25
O x = 625



• it’s A =5



Second part is
• it’s B =6

Answers

Answer:

x = 5

Step-by-step explanation:

Solve the equation in steps as below4 ln x = 2 ln 252 ln x = ln 252 ln x = ln 5²2 ln x = 2 ln 5ln x = ln 5x = 5
4lnx=2ln254lnx=2ln5²4lnx=4ln5lnx=ln5x=5

What is the remainder when dividing the sum (2001 + 2002 + 2003 + 2004 + 2005) by 2004?

Answers

Answer:

4.99750499002

Step-by-step explanation:

Answer:

1984

Step-by-step explanation:

(2001 + 2002 + 2003 + 2004 + 2005) by 2004

10015/2004

4 remainder 1984

Hope this helps!

please help ASAP!!!!!​

Answers

Answer:

that would be 26

Step-by-step explanation:

you got this!

If the base of a square building and an equilateral triangle building have the same perimeter,
how do the areas of their floors compare?

Answers

The relationship between the areas of the floors is [tex]A_s = \frac{3\sqrt 3}{4} A_t[/tex]

How to compare the areas?

Let the side length of the base of the square building be l, and the side length of the base of the equilateral triangle building be s

So, the perimeter of both buildings is

P = 4l --- the squareP = 3s --- the equilateral triangle

Both perimeters are equal.

So, we have:

4l = 3s

Divide both sides by 4

[tex]l = \frac 34s[/tex]

Square both sides

[tex]l^2 = \frac{9}{16}s\²[/tex]

The area of an equilateral triangle is:

[tex]A_t = \frac{\sqrt 3}{4}s^2[/tex]

And the area of a square is

[tex]A_s = l^2[/tex]

Make s^2 the subject in [tex]A_t = \frac{\sqrt 3}{4}s^2[/tex]

[tex]s^2 = \frac{4A_t}{\sqrt 3}[/tex]

Substitute [tex]s^2 = \frac{4A_t}{\sqrt 3}[/tex] and [tex]A_s = l^2[/tex] in [tex]l^2 = \frac{9}{16}s\²[/tex]

[tex]A_s = \frac{9}{16} * \frac{4A_t}{\sqrt 3}[/tex]

Evaluate

[tex]A_s = \frac{9}{4} * \frac{A_t}{\sqrt 3}[/tex]

Rationalize

[tex]A_s = \frac{3\sqrt 3}{4} A_t[/tex]

Hence, the relationship between the areas of the floors is [tex]A_s = \frac{3\sqrt 3}{4} A_t[/tex]

Read more about perimeter and area at:

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Graph the function f(x) = – 4(x + 4)2 square + 7.
Plot the vertex. Then plot another point on the parabola. If you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Answers

Vertex at (-4,7)

Graph attached

Answer:

vertex = (-4, 7)

(-3, 3) and (-2, -9)

(-6, -9) and (-5, 3)

Step-by-step explanation:

Given function:  [tex]f(x) = -4(x + 4)^2 + 7[/tex]

Vertex form of a quadratic function:  [tex]f(x)=a(x-h)^2+k[/tex]
(where (h, k) is the vertex)

From inspection, we can see that the given function is in vertex form.

h = -4 and k = 7

Therefore, the vertex is at (-4, 7)

As [tex]a[/tex] is negative, the parabola will open downwards.

When graphing functions, it is useful to determine the axis intercepts.

The curve will intercept the y-axis when x = 0.

Substituting x = 0 into the function:

[tex]f(0) = -4(0 + 4)^2 + 7=-57[/tex]

Therefore, the y-intercept is at (0, -57)

**cannot plot this on the given graph area as it is out of range**

The curve will intercept the x-axis when y = 0.

Setting the function to 0 and solving for x:

[tex]-4(x + 4)^2 + 7=0[/tex]

[tex]\implies -4(x + 4)^2=-7[/tex]

[tex]\implies (x + 4)^2=\dfrac74[/tex]

[tex]\implies x+4=\pm\sqrt{\dfrac74}[/tex]

[tex]\implies x=-4\pm\dfrac{\sqrt{7}}{2}[/tex]

Therefore, the x-intercepts are at (-2.7, 0) and (-5.3, 0) to 1 dp.

Finally, input values of x either sides of the x-intercepts for further plot points:

(-3, 3) and (-2, -9)

(-6, -9) and (-5, 3)

if amount is 7,500, time is 2years and rate is 10% then find principal?​

Answers

Answer:

Principal = $9,152.93

Step-by-step explanation:

A = $9,152.93

A = P + I where

P (principal) = $7,500.00

I (interest) = $1,652.93

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 10/100

r = 0.1 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 7,500.00(1 + 0.1/12)(12)(2)

A = 7,500.00(1 + 0.008333333)(24)

A = $9,152.93

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $7,500.00 at a rate of 10% per year compounded 12 times per year over 2 years is $9,152.93.

Given the rectangle below, find the measure of

Answers

Answer:

I don't know honestly sorry

Step-by-step explanation:

I tried

How many different 2-digit numbers can be formed with no digit repeated by using the digits 6, 1, 2, or 4?

Answers

Answer:

12

Step-by-step explanation:

61 62 64 16 12 14 26 21 24 46 41 and 42

If three folders cost $2.91 help us determine how much is two floders

Answers

I believe B is your answer :)

3. A Salesman Sold
$65,100 in bikes.
He eared a 20%
Commission. How
much did he earn?

Answers

Answer:

13020

Step-by-step explanation:

Answer:
He earned 13,020

Please help really quick I really need some help with this question

Answers

Answer:

first two are right because the scatterplots align well with both graphs in the direction described

Step-by-step explanation:

what is 3c2+ 2c- 16?
factoring​

Answers

Answer:

( c - 2 ) ( 3c + 8 )

Solution:

In the given question, we have to factorise the equation:

3c² + 2c - 16

Therefore, by using the middle term splitting method:

This method is used in equations which are in the form of ax² + bx + c. Here, we split the middle term into two terms which on multiplying gives ac and on adding or subtracting gives bx .

➙ 3c² + 2c -16

➙ 3c² - 6c + 8c - 16

➙ ( 3c² - 6c )+ (8c - 16 )

➙ 3c( c - 2 ) + 8 ( c - 2 )

➙ ( c - 2 ) ( 3c + 8 )

Factorisation of a quadratic polynomial of the type ax² + bx + c where (a ≠ 1) .

To factorise ax² + bx + c, we have to find two numbers whose sum is equal to the coefficient of x and product is equal to the coefficient of x² and constant term.

Consider the factorisation of 3c² + 2c – 16 .

We have to find two numbers whose sum is +2 and product (3 × 16) = 48 .

Obviously, the two numbers are 6 and 8 .

[tex]{ \qquad \sf { \dashrightarrow{ 3c {}^{2} + 2c - 16 }}}[/tex]

So, We can write it as,

[tex]{ \qquad \sf { \dashrightarrow{ 3c {}^{2} + 8c - 6c - 16 }}}[/tex]

[tex]{ \qquad \sf { \dashrightarrow{ c (3c + 8) -2 (3c + 8) }}}[/tex]

[tex]{ \qquad \sf { \dashrightarrow{ ( c -2 )(3c + 8) }}}[/tex]

In an election between two candidates, the winner received 65% of the 15,000 votes. The loser received the remaining votes. How many more votes did the winner receive than the loser?

Answers

Answer:The winner recieved 4,500 more votes than the loser

Step-by-step explanation:

Answer:

5,250

Step-by-step explanation:

The first step is to set up a porportion like this one

[tex]\frac{?}{15,000} \frac{65}{100}[/tex]

Next, you cross multiply and divide. 15,000 times 65 is 975,000

Then divide this by 100 which is 9750. This is the number of votes the winning candidate received. Subtract this number from 15,000 to get 5,250. Hope this helps!

What is the sum of the first 67 consecutive odd numbers

Answers

odd numbers are numbers which are divisible by 3,5,7 etc.....odd numbers between 60 and 70 are 63 65 67 and 69 the sum is 264

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