Identify the most and the least acidic compound in each of the following sets. Leave the remaining answer in each set blank. a) 2,4-dinitrobenzoic acid: _______ p-nitrobenzoic acid: _______ p-bromobenzoic acid: _______ b) oxalic acid: _______ acetic acid: _______ formic acid: _______ c) p-cyanobenzoic acid: _______ benzoic acid: _______ p-aminobenzoic acid:

Answer:

Option B, HCO3 1-

Explanation:

The valence of Sodium ion is +1 and the valence of HCO3 is -1. Thus, sodium ion has an extra electron to be donated to complete its outer shell  while HCO3 needs an electron to complete its outer shell

Hence Na will combine with HCO3 to form NaHCO3

Option B is correct

The polyatomic ion which will form an ionic compound with a single sodium ion is; HCO3 ¹-

In chemical bonding between ions;

The major criteria is a balance of charges within the compound formed.

As such, all polyatomic ions in the option are di-ionic except for HCO3 1- which can perfectly form an ionic compound with 1 single sodium ion.

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Answer:

option first is right answer

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

Where ΔG is Gibbs free energy = 12.86kJ/mol

R is gas constant = 8.314x10⁻³kJ/molK

T is absolute temperature = 298K

And K is equilibrium constant.

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

Answer:

Answer. Explanation: Chlorine gas bleaches the damp litmus (red or blue). Bleaching is an oxidation process.

Answer:

The answer is 200mL each amount have the same mass

Explanation:

100mL +100ML= 200mL mass in each container

Answer:

200ml

Explanation:

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer: OB. 1.806 x 1024

Explanation:

Answer:

181.403 g/mol is the answer as it is Zinc chromate

Explanation:

Answer:

181.403 g/mol

Explanation:

Molar mass of ZnCrO4 = 181.3737 g/mol. This compound is also known as Zinc Chromate. Convert grams ZnCrO4 to moles or moles ZnCrO4 to grams. 65.38 + 51.9961 + 15.9994*4

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

Answer:

As we move from left to right across a period, the ionization energy of elements increases. This is due to the decrease in the size of atoms across a period.

Answer:

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____________________

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Answer:

General Characteristics of Acids:

Sour taste (though you should never use this characteristic to identify an acid in the lab) Reacts with a metal to form hydrogen gas. Increases the H+ concentration in water. Donates H+ ions. Turns blue litmus indicator red.

Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

Moles of CaCO3 = 20 g/100 g/mol = 0.2 moles

Moles of NaNO3 = 2 × 0.2 moles = 0.4 moles

1 Mole of NaNO3 = 6.02 × 10²³ formula units

0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

Moles of oxygen gas produced = 10.93÷2 = 5.465 moles of oxygen gas

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

Moles potassium = mass/ molar mass

Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

Equation of the reaction:

[tex]\rm 2Na(No_3)+Ca(Co_3)---- > Na_2(Co_3)+Ca(No_3)_2[/tex]

[tex]NaNo_3\ and \ CaCo_3=\dfrac{2}{1}[/tex]

[tex]\rm Moles \ of \ CaCo_3=\dfrac{Mass}{Molar\ Mass}[/tex]

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

[tex]\rm \ Moles \ of \ CaCo_3=\dfrac{20}{100} =0.2[/tex]

[tex]Moles \ of \ NaNo_3=2\times 0.2=0.4\ moles[/tex]

[tex]1\ mole\ of \ NaNo_3=6.02\times10^{23}[/tex]

0.4 moles of NaNO3 = [tex]0.4\times 6.02\times 10^{23}=2.41\times 10^{23}[/tex]  

2. Equation of reaction :[tex]2H_2o---- > 2H_2+o_2[/tex]  

The mole ratio of oxygen to water =  [tex]\dfrac{2}{1}[/tex]

At STP contains

 [tex]\dfrac{6.02\times 10^{24}\times 1 \ mole \ of \ water}{6.02\times 10^{23}} =10.93\ moles \ of \ water[/tex]

Moles of oxygen gas produced =

[tex]\dfrac{10.93}{2} =5.465\ Moles \ of \ oxygen \ gas[/tex]

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas =    [tex]5.465\times 22.4=122\ L[/tex]  

3. Equation of reaction:

[tex]6k+N_2---- > 2K_3N[/tex]6

The mole ratio of Nitrogen gas and potassium =   [tex]\dfrac{6}{1}[/tex]

[tex]Moles\ of \ potassium = \dfrac{Mass}{Molar\ Mass}[/tex]

Mass of potassium = 90.0 g,

molar mass of potassium = 39.0 g/mol

[tex]Moles\ of \ potassium = \dfrac{90}{39}=2.3077\ moles[/tex]

[tex]Moles\ of \ Nitrogen = \dfrac{ 2.3077}{6}=0.3846\ moles[/tex]

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas =

[tex]0.3486\times 22.4=7.81\ L[/tex]

Thus

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

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Answer

0.32 is that answer

Explanation:

you just use the calculator

Answer:

At 10 ∘C , the solubility of potassium chloride is measured to be 31.2⋅g per 100⋅g of water.

Explanation:

Answer:

[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]

Explanation:

Hello there!

In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:

[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]

Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.

Best regards!

Answer:

the above answer is wrong

Explanation:

its really not but the mastering chemistry says it is

Answer:

probably the sun

.

Explanation:

because the sun's heat result to evaporation

Answer:

Pure substances are further divided into elements and compounds. The combination of two or more pure substances is called a mixture. Mixtures can be classified into two types viz. heterogeneous and homogeneous mixtures.

Explanation:

Answer:

The average kinetic energy has increased. More molecules have a higher energy level.

Explanation:

I so esay

Answer:

a. 87.8g/mol is the molar mass of the acid.

b. The answer is in the explanation.

Explanation:

To solve this question we must find the moles of the monoprotic acid using the reaction with NaOH (1mole of monoprotic acid reacts with 1 mole of NaOH). With the moles and the mass of the unknown we can find the molar mass.

Moles of NaOH added:

0.04121L * (0.150moles / L) = 6.1815x10⁻³ moles NaOH = Moles monoprotic acid

Molar mass is:

0.543g / 6.1815x10⁻³ moles = 87.8g/mol is the molar mass of the acid

b. I can't see the image you are giving because has a low resolution. But the identity of the acid can be obtained because the acid:

Has the same molar mass.

Is a monoprotic acid.

(a) The molecular mass of the unknown monoprotic acid will be 87.84 g/moles.

(b) The acid can be butyric acid, as it is a monoprotic and have mass near about 87.84 g/mol.

(a) The endpoint by the addition of NaOH has been reached when the monoprotic acid has been completely utilized. Since the NaOH has been monobasic. The moles of NaOH will be equal to the moles of acid.

Moles of NaOH = moles of acid

The molarity of NaOH = 0.15 M

Volume of NaOH = 41.21 ml

Molarity = [tex]\rm \dfrac{moles}{volume\;(L)}[/tex]

Moles = molarity [tex]\times[/tex] volume (L)

Moles of NaOH = 0.15 [tex]\times[/tex] 0.04121 L

Moles of NaOH = 0.00618 moles

Moles of NaOH = moles of acid

moles of acid = 0.00618 moles.

Mass of acid dissolved = 0.543 grams

Molecular weight of acid = [tex]\rm \dfrac{weight}{moles}[/tex]

Molecular weight of acid = [tex]\rm \dfrac{0.543}{0.006815}[/tex]

Molecular weight of acid = 87.84 g/moles.

(b) The acid with the molecular mass of 87.84 g/mol with being the monoprotic acid can be butyric acid. The butyric acid has a molecular weight of 88 g/mol.

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Answer:

Chlorine gas bleaches the damp litmus (red or blue). Bleaching is an oxidation process.

Explanation:

Answer:

Chlorine gas bleaches the damp litmus (red or blue). Bleaching is an oxidation process. If you are considering the colour change only - refer to it as bleaching. If you are considering the reaction mechanism and how the chemicals which provide the colour are changed, then refer to it as oxidation.

Explanation:

The formulas for the binary ionic compounds are:

We want to write the formulas of different binary ionic compounds. to do so, we need to consider the octet's rule.

The octet's rule establishes that atoms will lose, gain or share electrons to achieve the electron configuration of the nearest noble gas (8 valence electrons except for He with 2).

K has 1 valence electron so it will lose 1 electron to form K⁺. I has 7 valence electrons so it will gain 1 electron to form I⁻. The neutral compound between K⁺ and I⁻ is KI.

Mg has 2 valence electrons so it will lose 2 electrons to form Mg⁺². Cl has 7 valence electrons so it will gain 1 electron to form Cl⁻. The neutral compound between Mg⁺²⁺ and Cl⁻ is MgCl₂.

Na has 1 valence electron so it will lose 1 electron to form Na⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Na⁺ and S⁻² is Na₂S.

Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Al³⁺ and S⁻² is Al₂S₃.

Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. N has 5 valence electrons so it will gain 3 electrons to form N³⁻. The neutral compound between Al³⁺ and N³⁻ is AlN.

The formulas for the binary ionic compounds are:

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Answer:

option D

Explanation:

Increasing the temperature increases the yield of ammonia and speeds up the reaction as chemical reaction is affected by temperature.

Answer:

increasing the temperature decreases the yield of ammonia but speeds up the reaction

Explanation:

first pressure have no effect in chemical reaction

0.52 molar is the molarity of a solution in which 0.257 moles of HNO2 is dissolved in 490ml of water.

The term molarity is defined as the number of moles of solutes are dissolved in per litre of solution. It is represented by the symbol "M". The unit of molarity is molar(M).

To calculate the molarity of a solution, divide the moles of solute by the volume of the solution expressed in liters.

The formula of molarity = a number of moles of solutes /  litre of solution

Given:

Number of moles = 0.257 moles

Volume = 490ml = 0.49 litre

Molarity = ?

According to the definition of molarity,

Molarity = Number of moles of solute / litre of solution

Molarity =  0.257 moles / 0.49 litre

Molarity = 0.52 molar

Thus, the molarity of a solution in which 0.257 moles of HNO2 is dissolved in 490ml of water is 0.52 molar.

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Answer:

English Language Learners Definition of number. (Entry 1 of 2) : a word or symbol (such as "five" or "16") that represents a specific amount or quantity. : a number or a set of numbers and other symbols that is used to identify a person or thing.

Explanation:

79 is the number of protons gold has.

Hope this helps; have a great day!

Answer:

C. Carbon monoxide

This is my answer tell me if wrong

Ammonia among all the gases effuses most rapidly. Therefore, the correct option is option d.

A gas can escape or flow through a small aperture into a vacuum or a region with lower pressure through a process called effusion. It is a specific kind of gas flow that takes place in those circumstances. The square root of a gas's molar mass has an inverse relationship with the rate of effusion of that gas. The gas will effuse more quickly the lower the molar mass.

The molar mass are calculated as:

a. hydrogen chloride (HCl): H (1 g/mol) + Cl (35.5 g/mol) = 36.5 g/mol

b. nitrogen (N2): N (14 g/mol) + N (14 g/mol) = 28 g/mol

c. carbon monoxide (CO): C (12 g/mol) + O (16 g/mol) = 28 g/mol

d. ammonia (NH3): N (14 g/mol) + H (1 g/mol) + H (1 g/mol) + H (1 g/mol) = 17 g/mol

e. oxygen (O2): O (16 g/mol) + O (16 g/mol) = 32 g/mol

The square root of the molar masses are given as:

a. √36.5 ≈ 6.04

b. √28 ≈ 5.29

c. √28 ≈ 5.29

d. √17 ≈ 4.12

e. √32 ≈ 5.66

Ammonia has the lowest molar mass and hence the fastest effusion rate of all the gases.

Therefore, the correct option is option d.

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Answer - 1.50 M Na

Explanation -

3.00 moles of Na over 2.00 L of water.

3.00/2.00 = 1.50 M Na

I cannot be entirely sure. But it's an educated guess.