In 100 mL of cold water, 35 g of NaCl will dissolve, but 70 g will not. This observation implies that

Answer: They are the same species and have the same traits.

Explanation: These horses are well, the same species because they are horses.  They have very similar traits.  

Let me know if this is right!

Answer:

Energy is first released then arbsorbed the eventually it dissappears

Explanation:

The mass, in metric tons, of carbon in the methane is 1.83 metric tons

From the question, we are to determine the quantity of carbon in the methane

The mass of carbon in the methane can be calculated from

Mass of carbon in the methane = [tex]\frac{Mass\ of\ carbon\ in\ a\ molecule\ of \ methane}{Mass\ of\ a\ molecule\ of \ methane}\times Total\ mass\ of\ the\ methane[/tex]

Mass of carbon in a molecule of methane = 12 g

Mass of a molecule of methane = 16 g

Therefore,

Mass of carbon in the methane = [tex]\frac{12}{16} \times 2.44[/tex]

Mass of carbon in the methane = 1.83 metric tons

Hence, the mass, in metric tons, of carbon in the methane is 1.83 metric tons

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Answer:

Explanation:

Let the number of moles of water in the required formula be "y".

The final formula should be in the form of : CoCl2 yH2O

1.62 g is the weight of CoCl2 and water in the sample

After heating, the remaining mass represents  the mass the salt only

mass of water in sample = 1.62 - 0.88 = 0.74 g

From the periodic table:

molar mass of cobalt is 59 g

molar mass of chlorine is 35.5

molar mass of hydrogen is 1

molar mass of oxygen is 16

molar mass of formula = 59 + 2(35.5) + 18y = 130 + 18y g

Now we have calculate the mass/molar mass for each part of the formula (salt and water) and equate them to get number of moles of water as follows:

0.88 / 130 = 0.74 / y18

y = 6.07 which is approximately 6 moles

Thus, the final formula is CoCl2 6H2O. This hydrate is called cobalt(II)chloride hexahydrate.

give brainliest.

Answer:

initiated the comprehensive discovery and cataloguing of a 'parts list' of most human genes 

Explanation:

Graphite is a fantastic lubricant and a powerful electrical conductor because of these unbound electrons.

Unbound can serve as a caching server, it can also perform recursion, store records obtained from other DNS servers, and provide an authoritative service, such as if you only have a few zones.

As a result, it can act as a "glue" server or host a small zone with only a few domains, making it ideal for a lab.

Why need to utilize Unbound DNS?

With its harden-glue, access control, maximum randomization for request ID and ports, response scrubbing, case preservation, plus Denial of Service or DoS prevention capabilities, Unbound is feature-rich with DNS Security. These are only a few.

Therefore, graphite is a fantastic lubricant and a powerful electrical conductor because of these unbound electrons.

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#SPJ1

Answer:

The bulk of carbon dioxide is carried chemically combined with the amino acids of hemoglobin as carbaminohemoglobin in the RBCs.

6.15 grams of carbon dioxide is form when 8.94 g of oxygen is completely react.

Mass of any substance will be calculated from moles as :

n = W/M, where

W = required mass

M = molar mass

Given combustion reaction is:

CH₄ + 2O₂ → CO₂ + 2H₂O

Given mass of O₂ = 8.94 g

Molar mass of O₂ = 32.00 g/mole

Moles of O₂ = 8.94 / 32 = 0.279 mole

From the stoichiometry of the reaction, it is clear that:

2 moles of O₂ = produce 1 mole of CO₂

0.279 moles of O₂ = produce 1/2×0.279 = 0.139 moles of CO₂

Molar mass of CO₂ = 44 g/mole

Required mass of CO₂ will be calculated as:

W = n × M

W = 0.139 × 44 = 6.15 grams

Hence, option (2) is correct i.e. 6.15 grams.

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Answer:

Option 2/ B. 6.15 grams on edge.

Explanation:

S/o to the person above me, got it because of them.

Answer:

The formation of water from hydrogen and oxygen

Explanation:

Answer:

~Na+1 is already in the preferred form. Because of this, the second ionization energy of sodium is higher than normal. Mg+1 loses an electron to form s2 p6 .

Answer:

6 Energy levels

Explanation:

First Energy Level: 2

Second Energy Level: 8

Third Energy Level: 18

Fourth Energy Level: 25

Fifth Energy Level: 8

Sixth Energy Level: 2

Hope this helps.

Newton's third law

Explanation:

Answer 1 :

[tex]\green{\sf{D \: and \: E}}[/tex]

Step-by-step explanation:

As per graph, the highest lines are D and E. They are increasing.

Answer 2:-

[tex]\sf{\blue{B \: and \: C}}[/tex]

Step-by-step Explanation:

It is because the line between B and C is straight, indicating that it is steady.

Answer 3:-

[tex]\sf{\pink{2 \: m/s}}[/tex]

Step-by-step Explanation:

Its because the interval between line CD can be taken as-

[tex]\sf{40-50 = 1 m/s} \\ \sf{50-60 = 2 m/s}[/tex]

Hence, 2 m/s.

Answer 4:

[tex]\sf{\red{A \: and \: E}}[/tex]

Step-by-step Explanation:

We can see from the graph that the change in lines us occurring between initial and final points, i.e., between A and E.

Answer 5:

[tex]\sf{\purple{1m/s}}[/tex]

Step-by-step Explanation:

This is because, we can consider the interval between points D and E as :-

[tex]\sf{60-70=1m/s}[/tex]

Answer:

Oxygen is one of the most abundant elements on Earth. Oxygen accounts for 20.9% of the atmosphere, 45% of the Earth's crust (as oxide minerals) and also accounts for almost all of the mass of water on Earth (89%). It is found in a huge number of natural minerals including sulfates, phosphates, carbonates and oxides.

Explanation:

Hope this helps

Answer:

1.76g of N

Explanation:

5.04g x 1mol/16mol x 2mol/5mol x 14.01g/1mol = 1.76g

The amount of heat required to purify the Al is 25.94 * 10^3 J

The term heat capacity refers to the amount of heat required to raise the temperature of a substance by 1K. The aluminum was heated from 298 K to 933 K then it melted.

The total heat required is;

H = ncdT + nL

H = (1 * 24 * (933 - 298)) + (1 * 10.7 * 10^3)

H = 15.24 * 10^3  J + 10.7 * 10^3 J

H = 25.94 * 10^3 J

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6 M is the molarity of the HCl solution with volume 1 liter.

Molarity (M) of solution is define as the number of moles (n) of solute present in per liter (V) of solution, i.e. M = n/V.

Given chemical reaction is:

2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O

Given volume of HCl = 1 L

Given volume of Ca(OH)₂ = 2 L

Molarity of Ca(OH)₂ = 1.50M

Moles of Ca(OH)₂ = 1.50 × 2 = 3 moles

From the stoichiometry of the reaction:

1 mole of Ca(OH)₂ = react with 2 moles of HCl

3 mole of Ca(OH)₂ = react with 2×3=6 moles of HCl

Molarity of HCl will be calculated by using the above given formula as:

M = 6/1 = 6M.

Hence, option (4) is correct i.e. 6 M.

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Answer:

D

Explanation:

trust

Answer:

B, E

Explanation:

Edge

Answer:

the pOH of a solution is the negative logarithm of the hydroxide-ion concentration. by this yields a [OH − ] of 1.0 × 10 -10 M. Finally the pOH of the solution equals -log(1.0 × 10 -10 ) = 10.Explanation:

The concentration of hydroxide ion of a solution whose pOH value is equal to 2.86 is 1.38×10⁻³ M.

Concentration of hydroxide ion will be calculated by using the pOH value by using the below equation as:

pOH = -log[OH⁻]

[OH⁻] = [tex]10^{-pOH}[/tex]

Given that value of pOH = 2.86

On putting values we get,

[OH⁻] = [tex]10^{-2.86}[/tex]

[OH⁻] = 0.00138 = 1.38×10⁻³ M

Hence concentration of hydroxide ion is 1.38×10⁻³ M.

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Answer:

Its C

Explanation:

If you look, you can see that it tells you the humidity and the that its warm but it also tells you that it storms a little to and that makes it easier to know the climate but if it just sayed it was warm that wouldn't be enough information

CAN I PLS HAVE BRAINLIEST. I NEVER GET IT. ITS A LITTLE CROWN UNDER MY ANSWER. PLS. ILL GIVE YOU BRAINLIEST JUST PLS

Answer:

C3H8

Explanation:

1 1.5mol

2 0.75mol

3 0.667mol

Questions 1.2

1 16.7mol

2 8.3×10−3mol

Questions 1.3

1 9

2 11

3 12

4 24

5 22

Questions 1.4

1 a) 151.9

b) 162.1

c) 60.0

d) 132.1

e) 388.8

2 a) 0.5mol

b) 2.5mol

c) 0.6mol

d) 2.0mol

e) 0.38mol

3 a) 180.6g

b) 44.46g

Questions 1.5

1 Mr = 277.9 moles of oxygen = 11

2 Mr = 474.3 moles of oxygen = 20

Questions 1.6

1 Cu2S

2 C3H8

3 CaFe2O4

Questions 1.7

1 a) 2H2 + O2 → 2H2O

b) I2 + 3Cl2 → 2ICl3

c) NaOH + Al(OH)3 → NaAlO2 + 2H2O

d) 2H2S + SO2 → 3S + 2H2O

e) 4NH3 + 3O2 → 2N2 + 6H2O

2 a) MgCO3 → MgO + CO2

b) Pb(s) + 2AgNO3(aq) → Pb(NO3)2(aq) + 2Ag(s)

c) Na2O(s) + H2O(l) → 2NaOH(aq)

d) 2FeCl2 + Cl2 → 2FeCl3

e) Fe2(SO4)3 + 6NaOH → 2Fe(OH)3 + 3Na2SO4

Questions 1.8

1 17.0g

2 60.7g

3 51.1%

Questions 1.9

1 1.2dm3

2 Volume of SO2 = 50cm3; mass of sulfur = 0.20g

Questions 1.10

1 a) 2.67moldm−3

b) 0.025moldm−3

c) 0.833moldm−3

2 a) 0.75mol

b) 0.044mol

c) 0.010mol

Answer:

that's not good

Explanation:

microbes???? not good for a sewage system

Answer

changing from liquid to gas

Explanation

changing from liquid to gas

Answer:

1.7

Explanation:

  1 grams Water to mol = 0.05551 mol

30 grams Water to mol = 1.66525 mol

if we round that up the answer is 1.7

25.07grams is the theoretical yield of magnesium hydroxide if the resulting solution has a volume of 2. 82 liters.

Mass of any substance will be calculated from moles as:

n = W/M, where

W = given or required mass

M = molar mass

Given chemical reaction is:

2NaOH + MgCl₂ → Mg(OH)₂ + 2NaCl

From the stoichiometry of the reaction, it is clear that:

2 moles of NaOH = produce 1 mole of Mg(OH)₂

1 mole of NaOH = produce 1/2 mole of Mg(OH)₂

Given concentration of NaOH = 1.35M

Given volume of NaOH = 637mL = 0.637L

Moles of NaOH will be calculated as:

M = n/V

n = 1.35M × 0.637L = 0.859 moles

So, 0.859 moles of NaOH = produce 0.859×1/2 = 0.429 moles of Mg(OH)₂

Now, we convert this moles into grams by using the above formula:

0.429 = W/58.31 g/mole

W = 25.07grams

Hence, 25.07grams is the theoretical yield of magnesium hydroxide.

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Answer:

Explanation:

Salt + water gives an adequate conductor. It is not absolutely wonderful like silver, but it will conduct electricity to varying degrees depending on the depth of salt water that the conductor is held at.

I'd say A.

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log(2.4\times 10^{-6})[/tex]

[tex]\\ \rm\Rrightarrow pH=-log2.4-log10^{-6}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.38+6[/tex]

[tex]\\ \rm\Rrightarrow pH=5.62[/tex]