In Exercises 37– 40, BD ⃗ bisects ∠ABC. Find m∠ABD,

m∠CBD, and m∠ABC.

In Exercises 37 40, BD Bisects ABC. Find MABD,mCBD, And MABC.

Answers

Answer 1

Answer:

37,  ABD = CBD = 44 degrees, and ABC = 88 degrees

38.  ABD = CBD = 24 degrees, and ABC = 48 degrees

39.  ABD = CBD = 65 degrees, and ABC = 130 degrees

40.  ABD = CBD =67 degrees, and ABC = 134 degrees

Step-by-step explanation:

Recall that when a segment bisects an angle, the angle is divided in equal parts then we have:

37.  

6 x + 14 = 3 x + 29

3 x = 19 - 14 = 15

x = 15/3

x = 5

then ABD = 6 (5) + 14 = 30 + 14 = 44 degrees

CBD must equal ABD , so CBD = 44 degrees

And the total angle ABC = 88 degrees

38.

3 x + 6 = 7 x - 18

24 = 4 x

x = 24/4 = 6

Then ABD = 3 (6) + 6 = 24 degrees. Also CBD = 24 degrees and ABC = 48 degrees

39.

- 4 x + 33 = 2 x + 81

- 6 x = 81 - 33

-6 x = 48

x = - 48/6

x = -8

Then ABD = -4 (-8) + 33 = 32 + 33 = 65 degrees

The also CBD = 65 degrees, and ABC = 130 degrees

40.

8 x + 35 = 11 x + 23

35 - 23 = 11 x - 8 x

12 = 3 x

x = 12/3

x = 4 degrees

Therefore:

ABD = 8 (4) + 35 = 32 + 35 = 67 degrees.

Then also CBD = 67 degrees, and ABC = 134 degrees


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Answers

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Answers

Answer:

.

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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[tex]=5^{4} * 7^{5}* 2^{8} /2^{4} *5^{3} *7^{3}[/tex]

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Answer:

Step-by-step explanation:

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[tex]\frac{5^{4}*7^{5}*2^{8}}{16*125*7^{3}}=\frac{5^{4}*7^{5}*2^{8}}{2^{4}*5^{3}*7^{3}}\\\\\\=5^{(4-3)}*7^{(5-3)}*2^{(8-4)}\\\\\\=5^1*7^2*2^{4}[/tex]

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Answers

Answer:

Step-by-step explanation:

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Answers

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Answers

Hey there! I'm happy to help!

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Have a wonderful day! :D

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Answers

Answer:

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Step-by-step explanation:

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Answers

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