Mhanifa please help i will mark brainliest

Answer:

BE = 3.5 m

Step-by-step explanation:

Δ ACB and Δ EDB are similar, so the ratios of corresponding sides are equal, that is

[tex]\frac{BE}{BA}[/tex] = [tex]\frac{BD}{BC}[/tex] , substitute values

[tex]\frac{BE}{21}[/tex] = [tex]\frac{3}{18}[/tex] ( cross- multiply )

18 BE = 63 ( divide both sides by 18 )

BE = 3.5

Answer:

he can buy 6 gift cards, 7 theatre cards with a remainder of $10.

Step-by-step explanation:

Answer:

The angles are acute and x should be 243. Not sure if that's what you are looking for but good luck!

Answer:

I need to know the choices in the blank box before I answer that part of the question.

Step-by-step explanation:

180-117=63

x=63

Answer:

Ggggggggggggggggggggg!!!

Step-by-step explanation:

Answer:

1. a

2. d

3. c

4. d?

5. cant answer cause I cannot see the data

Answer:

A = 68

B = 44

C = 68

Step-by-step explanation:

find x:

68 + x + x - 24 = 180

2x + 44 = 180

180 - 44 = 136

136 / 2 = 68

x = 68

_________________________

68 + 68 + 44 = 180

Answer:

Height of building = 86.9 ft

Step-by-step explanation:

I've drawn a triangle image to depict this question and I have attached it.

From the attached image, we can see that ABC is the height of the building.

We can see the distance from your eye to the ground indicated and also the distance from the horizontal distance from the building to you indicated.

We can use pythagoras theorem to find AB.

AB/57 = tan 55°

AB = 57 × 1.4281

AB = 81.4 ft

Now, total height of the building is AB + BC.

BC = 5.5 ft since B is parallel to your eye and height from there to the ground is 5.5 ft.

Thus;. Height of building = 81.4 + 5.5 = 86.9 ft

Answer:

The answer is A

Step-by-step explanation:

edge21

The statement which is true of the right triangles ABC and DEF is Area of ABC is greater than area of DEF.

Right angled triangle are those triangle for which one of the angle is 90 degrees.

Given two right angled triangles, ABC and DEF.

Area of a triangle = 1/2 × base × height

Area of ΔABC = 1/2 × 14 × 6

                        = 42 square units

Base of ΔDEF = √(7² + 4²) = √65

Height of ΔDEF = √(5² + 8²) = √89

Area of ΔDEF = 1/2 × √65 × √89

                       = 38.03 square units

Hence the correct option is Area of ABC is greater than area of DEF.

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Answer:

17,160

Step-by-step explanation:

250. Milliliters = 12 minutes

1 liter= 250/12

= 20.83

Therefore the time required to reach 825 ministers

= 825×20.8

= 17,160

Hence the time needed is 17, 160

Answer:

5.6 miles per gallon

Step-by-step explanation:

Equation for Mrs Sanchez: y = 36x

The rate of change = miles/gallon for Mrs Sanchez = 36 miles/gallon

Let's find the rate of change for Mr White:

Rate of change = change in y/change in x

Using two pairs of values form the table given, (2.5, 76) and (5, 152),

Rate of change = (152 - 76)/(5 - 2.5) = 76/2.5

Rate of change = miles/gallon = 30.4 miles/gallon

The difference between the miles per gallon of Mrs Sanchez and Mr White = 36 - 30.4 = 5.6 miles per gallon.

Therefore, Mrs Sanchez gets 5.6 miles per gallon than Me White

Answer:

I think it's 25

Step-by-step explanation:

I used a protractor

Answer:

Corresponding Angles:

∠2 and ∠6

∠4 and ∠8

∠1 and ∠5

∠3 and ∠7

Vertical Angles:

∠2 and ∠3

∠1 and ∠4

∠5 and ∠8

∠6 and ∠7

Alt. Interior:

∠4 and ∠5

∠5 and ∠6

Alt. Exterior:

∠2 and∠7

∠1 and∠8

Step-by-step explanation:

This took me forever..

Answer:

yeah same for me but with ice cream

Answer:

6 feet

Step-by-step explanation:

Given that,

The perimeter of the square, P = 24 feet

We need to find the side of the square.

The perimeter of a square is given by the formula as follows :

[tex]P=4a[/tex]

Where

a is the side length

So,

[tex]a=\dfrac{P}{4}\\\\a=\dfrac{24}{4}\\\\a=6\ feet[/tex]

So, the side of each log be 6 feet.

Circumference of Circle :-

[tex] \sf \underline{\pink{\boxed{2\pi r}}}[/tex]

Value of π (pi) =

[tex] \sf \: { \frac{22}{7} } \: or \: 3.14[/tex]

9) C = 2πr = 2 × 3.14 × 4

≈ 25.13274

10) C = 2πr = 2 × 3.14 × 7.2

≈ 45.23893

11) C = 2πr = 2 × 3.14 × 10

≈ 62.83185

12) C = 2πr = 2 × 3.14 × 3.6

≈ 22.61947

13) Given :-

Diameter : 8m

Radius = half of D = 4 cm

⇢C = 2πr = 2 × 3.14 × 4

≈ 25.13274

14) Radius = 6 cm

C = 2πr = 2 × 3.14 × 6

≈ 37.69911

15) C = 2πr = 2 × 3.14 × 7.1

≈ 44.61

16) C=2πr=2× 3.14 × 5.2

≈ 32.6

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[tex]{\huge{\underline{\small{\mathbb{\pink{HOPE \ THIS \ HELPED \ UH:)}}}}}}[/tex]

Answer:

the answer is C

Step-by-step explanation:

Answer:

Bottom Left is the right answer

Step-by-step explanation:

ig hanganaahajssislaalalla

Answer:

a. The distance the train travelled in the first hour is approximately 28.3 miles

b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west

c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)

d. The train does not collide with the cyclist when the bike goes over the train tracks

Step-by-step explanation:

a. The given information on the train's motion are;

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour

Making use of the coordinate plane for the two locations the train was spotted, we have;

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;

[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Therefore;

[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]

The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles

b. The speed of the train, v = (Distance travelled by the train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;

[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

Where;

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have;

y = -10 + 15·t

The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.

If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Thus, the difference between the two times the train was spotted,

t = 3:00 p.m. - 2:00 p.m. = 1 hour

The distance is the product of velocity and time.

Distance = Velocity × Time

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour

[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]

d = 3√89

The distance the train travelled in the first hour, d = 28.3 miles

b. The speed of the train, v = (Distance travelled by train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;

∴ m = tan(θ) = (5 - (-10))/(16 - (-8))

m = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is, therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity,

= 3 × √89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have

y = -10 + 15·t

The x-component of the velocity,

vₓ = 3 × √89 mph × cos(arctan(0.625))

= 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't',

f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept

                                                                   = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8)

= (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

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Kevin knit 9 scarves, and each scarf was 49.2 inches long.

Converting this length to feet, we find that each scarf is 4.1 feet long.

Let's use the variable "L" to represent the length of each scarf in inches. Since Kevin knit 9 scarves, we can write the equation for the total length of all scarves as:

[tex]\(L_{\text{total}} = L \times 9\)[/tex]

We are given that the total length of all scarves is 442.8 inches. So, we can write:

[tex]\(442.8 \text{ inches} = L \times 9\)[/tex]

To find the length of each scarf, we need to isolate "L" on one side of the equation. To do that, we can perform the following steps:

Divide both sides of the equation by 9 to get:

[tex]\(\frac{{442.8 \text{ inches}}}{{9}} = \frac{{L \times 9}}{{9}}\)[/tex]

Simplifying, we get:

[tex]\(49.2 \text{ inches} = L\)[/tex]

Now, we have found the length of each scarf in inches (49.2 inches). To convert this length to feet, we know that 1 foot is equal to 12 inches. So, to find the length in feet, we divide the length in inches by 12:

[tex]\(L_{\text{feet}} = \frac{{L_{\text{inches}}}}{{12}}\)[/tex]

Substituting the value of [tex]\(L_{\text{inches}}\)[/tex] with 49.2 inches:

[tex]\(L_{\text{feet}} = \frac{{49.2 \text{ inches}}}{{12}}\)[/tex]

Now, let's perform the division:

[tex]\(L_{\text{feet}} = 4.1 \text{ feet}\)[/tex]

So, each scarf is 4.1 feet long.

Kevin knit 9 scarves, and each scarf was 49.2 inches long.

Converting this length to feet, we find that each scarf is 4.1 feet long.

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Answer:

16 hats

Step-by-step explanation:

8h+12s=272

h+s=28

isolate s to get s=28-h

substitute that in for s and solve for h

you will get h=16 meaning 16 hats were sold

Answer:

D.

Step-by-step explanation:

The situation that can be modeled by the expression -3/4 x 2/5  is:

Abdi owes Kim 3/4 of a dollar. He pays her 2/5 of how much he owes.

The expression -3/4 x 2/5 gives us the fraction of a dollar that Kim receives from Abdi, which is -3/10 of a dollar.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

The expression -3/4 x 2/5 means that we multiply -3/4 by 2/5.

Multiplying two fractions involves multiplying their numerators together and their denominators together. So,

-3/4 x 2/5 = (-3 x 2) / (4 x 5) = -6/20 = -3/10

Therefore,

The situation that can be modeled by the expression -3/4 x 2/5  is:

Abdi owes Kim 3/4 of a dollar. He pays her 2/5 of how much he owes.

The expression -3/4 x 2/5 gives us the fraction of a dollar that Kim receives from Abdi, which is -3/10 of a dollar.

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Answer:

area = 12.6 m²

Step-by-step explanation:

r = 4/2 = 2

area = πr² = (3.14)(2²) = 12.56 m²

Answer:

30 ft

Step-by-step explanation:

[tex]C=\frac{n^2}{5} +175\\\\355=\frac{n^2}{5} +175\\\\180=\frac{n^2}{5}\\\\n^2=900\\\sqrt{n^2} =\sqrt{900} \\n=30[/tex]

Answer:

It's the third option

Step-by-step explanation:

One sides needs to have Lunches and the other needs to have how many is sold

It also needs to be clear and option 2 Is not as clear as 1 and 3

the only options that leaves us is 1 and 3

option 1 has the wrong labels

so.it is OPTION 3

Answer:

. Statement. 1. AD ≅ CE & DB ≅ EB Side. 2. ∠B ≅ ∠B Angle. 3. AD + DB ≅ CE + EB or AB ≅ BC Side. 4. ΔABE ≅ ΔBCD. 5. ∠1 ≅ ∠2. 6. ∠1 & ∠3

Step-by-step explanation:

a. To find the amount of the down payment, we need to multiply the price of the home by the percentage of the down payment required.

How would one define compounding?

Compounding is the method through which interest is added to both the principle balance already in place and the interest that has already been paid. Thus, compounding can be thought of as interest on interest, with the result that returns on interest are magnified over time, or the so-called "magic of compounding."

The price of the home is $456,500 and the down payment percentage is 20%, so:

Down payment = $456,500 x 20% = $456,500 x 0.20 = $91,300

b. To find the amount of the mortgage loan, we can subtract the down payment from the price of the home.

The price of the home is $456,500 and the down payment is $91,300 so:

Mortgage loan = $456,500 - $91,300 = $365,200

Therefore, the amount of the down payment is $91,300 and the amount of the mortgage loan is $365,200.

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