Quadrilateral ABCD ~ quadrilateral JKLM. What is the
length of LM?

Quadrilateral ABCD ~ Quadrilateral JKLM. What Is Thelength Of LM?

Answers

Answer 1

Step-by-step explanation:

just ratio and need to identify which lines are pairs.

Quadrilateral ABCD ~ Quadrilateral JKLM. What Is Thelength Of LM?

Related Questions

2.
Show your work
24*
V
2x
Angle =

Answers

Answer:

90-24=76°

Step-by-step explanation:

____________________

What is (f-g)(x)?
F(x)=3x5+6x2-5
G(x)=3x5-5x4+3x2-15

What is (f•g)(x)?
F(x)=x3-4x+2
G(x)=x2-6

Answers

The resulting function is (f-g)(x) = 5 · x⁴ + 3 · x² + 10.

The resulting function is (f • g) (x) = 3 · (3 · x⁵ - 5 · x⁴ + 3 · x² - 15)⁵ + 6 · (3 · x⁵ - 5 · x⁴ + 3 · x² -15)² - 5.  

How to apply subtraction between two functions

Let be [tex]f(x)[/tex] and [tex]g(x)[/tex] polynomial functions, the subtraction between between the two functions implies the subtraction of similar terms. If we know that [tex]f(x) = 3\cdot x^{5}+6\cdot x^{2}-5[/tex] and [tex]g(x) = 3\cdot x^{5}-5\cdot x^{4}+3\cdot x^{2}-15[/tex], then the subtraction between the two functions:

[tex](f-g)(x) = (3\cdot x^{5}+6\cdot x^{2}-5)-(3\cdot x^{5}-5\cdot x^{4}+3\cdot x^{2}-15)[/tex]

[tex](f-g)(x) = 5\cdot x^{4}+3\cdot x^{2}+10[/tex]

The resulting function is (f-g)(x) = 5 · x⁴ + 3 · x² + 10. [tex]\blacksquare[/tex]

How to apply composition between two functions

The composition between two functions, the independent variable of the former function by the latter function. If we know that [tex]f(x) = 3\cdot x^{5}+6\cdot x^{2}-5[/tex] and [tex]g(x) = 3\cdot x^{5}-5\cdot x^{4}+3\cdot x^{2}-15[/tex], then the composition between the two functions:

[tex]f\,\circ\,g\,(x) = 3\cdot (3\cdot x^{5}-5\cdot x^{4}+3\cdot x^{2}-15)^{5}+6\cdot (3\cdot x^{5}-5\cdot x^{4}+3\cdot x^{2}-15)^{2}-5[/tex]

(f • g) (x) = 3 · (3 · x⁵ - 5 · x⁴ + 3 · x² - 15)⁵ + 6 · (3 · x⁵ - 5 · x⁴ + 3 · x² -15)² - 5.  [tex]\blacksquare[/tex]

To learn more on functions, we kindly invite to check this verified question: https://brainly.com/question/5245372

Need help please with this math question

Answers

Answer:

1/20=5%

Step-by-step explanation:

I just need the answers

Answers

Answer:

A=102 and B=0

Step-by-step explanation:

Sub values for X and Y into equation, put into your calculator and you will get the correct answer.

Answer:

a) 102

b) 0

Step-by-step explanation:

A:

[tex]10(10)-(2(5)-12)[/tex] [tex]100-(10-12)[/tex] [tex]100-(-2)[/tex]  [tex]100+2[/tex] [tex]102[/tex]

B:

[tex]2\left(10\right)-35+4\left(10\right)-\left(3\left(10\right)-5\right)[/tex] [tex]20-35+40-(30-5)[/tex] [tex]25-(25)[/tex] [tex]0[/tex]

What quadratic function bests fits this data?
(refer to the picture)
A) y= -9.38x^2 + 74.80x + 186.1
B) y= -9.38x^2 -74.80x+186.1
C) y= 9.38x^2 - 74.80x + 186.1
D) y= 9.38x^2 + 74.8x + 186.1

Answers

The third one: 9.38x^2 - 74.80x + 186.1

NO LINKS!!! Part 7: Please help me with this problem​

Answers

Apply law of cosines

[tex]\\ \rm\longmapsto c^2=a^2+b^2-2abcos\gamma[/tex]

[tex]\\ \rm\longmapsto c^2=150^2+35^2-2(150)(35)cos110[/tex]

[tex]\\ \rm\longmapsto c^2=22500+1225-10500(-0.34)[/tex]

[tex]\\ \rm\longmapsto c^2=23725+3570[/tex]

[tex]\\ \rm\longmapsto c^2=27295[/tex]

[tex]\\ \rm\longmapsto c=165.2yd[/tex]

Answer:

165 yd (nearest yard)

Step-by-step explanation:

To calculate the distance from the ball to the center of the green, we need to use the cosine rule:

[tex]c^2=a^2+b^2-2ab \cos (C)[/tex]

where:

C is the anglea and b are the sides adjacent to the angle Cc is the side opposite the angle C

Therefore, for this triangle:

a = 35 ydb = 150 ydC = 110°

Substituting these values into the cosine rule formula:

[tex]\implies c^2=35^2+150^2-2(35)(150) \cos (110\textdegree)[/tex]

[tex]\implies c^2=23725-10500\cos(110\textdegree)[/tex]

[tex]\implies c=\sqrt{23725-10500 \cos(110\textdegree)}[/tex]

[tex]\implies c=165.2761674...[/tex]

[tex]\implies c = 165 \textsf{ yd (nearest yard)}[/tex]

Question 2 of 10
What is the first step in solving a quadratic equation of the form given below?
(ax + b)2 = 0
A. Take the square root of both sides
B. Factor out a common factor
C. Divide both sides by c
D. Use the zero product rule
SUBMIT

Answers

Step-by-step explanation:

a.

(ax + b)² = 0

√( (ax + b)²  )= √0

ax + b = 0

dont know the rest

Give an equation in standard form for a line which is perpendicular to -2x + 3y = 7 and has a y intercept of -3.

Answers

Answer:

y=-3/2x-3

Step-by-step explanation:

For perpendicular lines,the product of their slopes is -1 this m1•m2=-1

For the given line 3y=7+2x

y=7/3+⅔x,the slope is ⅔

For the unknown line since the y-intercept is -3 then y=mx-3

compare the slopes of both lines

m•⅔=-1

m=-3/2

hence the the perpendicular line has the equation

y=-3/2x-3

If the scale factor of sides is 3, then the scale factor of area is ___ and the scale factor of
volume is __

Answers

Answer:

9

27

Step-by-step explanation:

the scale factor of area is 3² = 9

the scale factor of volume is 3³ = 27

Answer:

1/2 then 4Ts

Step-by-step explanationexplanation: good luck

suppose there is a normally distributed population with a mean of 250 and a standard deviation of 50. if xbar is the average of a sample of 36, find P(246

Answers

Using the normal distribution and the central limit theorem, it is found that:

[tex]P(246 \leq \bar{x} \leq 260) = 0.5693[/tex]

Normal Probability Distribution

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem:

The mean is of [tex]\mu = 250[/tex].The standard deviation is of [tex]\sigma = 50[/tex].A sample of 36 is taken, hence [tex]n = 36, s = \frac{50}{\sqrt{36}} = 8.3333[/tex].

The probability of a sample mean between 246 and 260 is the p-value of Z when X = 260 subtracted by the p-value of Z when X = 246, hence:

X = 260:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{260 - 250}{8.3333}[/tex]

[tex]Z = 1.2[/tex]

[tex]Z = 1.2[/tex] has a p-value of 0.8849.

X = 246:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{246 - 250}{8.3333}[/tex]

[tex]Z = -0.48[/tex]

[tex]Z = -0.48[/tex] has a p-value of 0.3156.

0.8849 - 0.3156 = 0.5693, hence:

[tex]P(246 \leq \bar{x} \leq 260) = 0.5693[/tex]

To learn more about the normal distribution and the central limit theorem, you can check https://brainly.com/question/24663213

Please help!!!!!!!!!!!!

Answers

the answer is F false

Brainliest if correct

Answers

Answer:

44% is shaded

Step-by-step explanation:

Having carefully counted, I find 44 of the squares shaded. I'm sure of it.

Answer:

Yes, the other is correct. The answer is 44%

Step-by-step explanation:

help I need the answer now :(​

Answers

Answer:

  E, F, A, ED, BC, EF, ABC, EDF

Step-by-step explanation:

The angle and side markings show which segments and angles are congruent.

We can make a table of corresponding pairs based on the number of marks:

marks, angle, side

A and E, DF and BCB and D, ED and ABC and F, EF and AC

__

This can help us fill in the question numbers:

∠E is congruent to ∠A∠F is congruent to ∠C∠A is congruent to ∠EED is congruent to ABBC is congruent to DFEF is congruent to AC8. ΔABCΔEDF

Zeke bought 10 shares of a company’s stock at a price of $21.20 per share. He now sees that the price per share of his investment is $32. His broker informs him that the price of the shares may see a decline in the future.

Zeke should ideally
the assets because he stands to earn a profit of
per share from the transactio

Answers

Answer:

Sell, 10.80

Step-by-step explanation:

PLATO Users be like

Help with graphing rational functions

Answers

Answer: A


Explanation:

Asymptote at x = -2,1

Asymptote is when a number is divided by 0.

Plug in x = -2,1 in the function and both give you a number divided by zero

Factor the greatest common factor (GCF) from each polynomial. - 12y + 48x ​

Answers

Answer:

-12(y-4x)

Step-by-step explanation:

-12y+48x=-12(y-4x)

Una persona que se dirige desde su casa hasta el colmado hay una longitud de 10 metros , luego la persona regresa a su casa que desplazamiento y distancia usted recorre?

Answers

Veremos que la distancia total recorrida es de 20 metros, y el desplazamiento es de 0 metros.

¿Cuanto es el desplazamiento?

Definimos el desplazamiento como la diferencia entre la posición final y la inicial. En este caso sabemos que la persona comienza en su casa, luego va al colmado, y luego regresa a su casa.

Entonces la posicion inicial y la final son la misma, por lo que concluimos que el desplazamiento es 0.

¿Cuanta distancia se recorre?

La distancia total recorrida será igual a dos veces la distancia entre la casa y el colmado.

Esta distancia es 10 metros, entonces la distancia recorrida es:

distancia = 2*10m = 20m

Sí quieres saber mas sobre desplazamientos, puedes leer:

https://brainly.com/question/4931057

Show Intr
Maggie can do a job in 15 hours less than Ryan can. If they work together they can get the job done in 10 hours. How long would it take cach to do the job alone?
Maggie can do the job in
hours
Ryan can do the job in
hours

Answers

Answer:

Maggie = 15 hours

Ryan = 30 hours

Step-by-step explanation:

let x - time it takes Ryan to do the job alone.

x-15 - time it takes Maggie to do the job alone

[tex] \frac{10}{x} + \frac{10}{x - 15} = 1 \\ \\ \frac{10(x - 5) + 10x}{x(x - 15)} = 1[/tex]

[tex]10x - 150 + 10x = x {}^{2} - 15x \\ \\ 20x - 150 = x {}^{2} - 15x \\ \\ x {}^{2} - 15x - 20x + 150 = 0 \\ \\ x {}^{2} - 35x + 150 = 0 \\ \\ (x - 30)(x - 5) = 0 \\ \\ x = 30 \: and \: x - 15 = 15[/tex]

x = 5 --> not valid because x-15 will be NEGATIVE

Therfore,

Maggie can do the job in 15 hours.

Ryan can do the job in 30 hours.

A grocery store clerk put only packages of Takis and packages of Flamas on a shelf. The ratio of the number of packages of Flamas to the total number of packages on the shelf was 9 to 16.
Which number could be the number of packages of Takis the clerk put on the shelf?

Answers

Answer:

5 packages of Takis

Step-by-step explanation:

The total number packages that were placed on the shelf were 16 packages. The total number of packages of Flamas that were placed on the shelf were 9 packages. So to identify the number of packages of Takis the clerk put on the shelf, we simply do

16-9=5

Find all points on the​ x-axis that are 16 units from the point (4,-8)

Answers

Step-by-step explanation:

all points on the x axis have a y value of 0.

so, we need to find all points (x, 0) with a distance of 16 to (4, -8).

the distance to a point is the Hypotenuse of the right-angled triangle with the coordinate differences as legs.

and so Pythagoras applies :

c² = a² + b²

with c being the Hypotenuse (side opposite of the 90° angle).

so, in our case we have

16² = (4-x)² + (-8 - 0)²

256 = 16 - 8x + x² + 64 = x² - 8x + 80

x² - 8x - 176 = 0

if we have no other idea of factorization the general solution of such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -8

c = -176

x = (8 ± sqrt((-8)² - 4×1×-176))/(2×1) =

= (8 ± sqrt(64 + 704))/2 = (8 ± sqrt(768))/2 =

= (8 ± sqrt(256×3))/2 = (8 ± 16×sqrt(3))/2 =

= 4 ± 8×sqrt(3)

x1 = 4 + 8×sqrt(3) = 17.85640646...

x2 = 4 - 8×sqrt(3) = -9.856406461...

so, the points on the x axis that are 16 units apart from (4, -8) are

(x1, 0) and (x2, 0)

I am not sure in what format you need the answer.

please fill in for x1 and x2 from above what you need.

Help!!!! I don't know how to do this stuff..

Answers

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

The y - intercept of the shown line on the graph is -4

Y - intercept is the " y - coordinate of the point on line when it cuts the y - axis "

What fractions represents the shaded boxes?

Answers

Answer:

7/10 is the fraction that Represents the shaded boxes.

I think it will help you.

Answer:

7/10

Step-by-step explanation:


dog weighs 20% more than it did three months ago. It
weighs 36 pounds now.
How much did the dog weigh three months

Answers

28.8 pounds

20% of 36= 7.2

36-7.2= 28.8

Answer:

weight dog trhee monts ago is 28.i pounds

Step-by-step explanation:

Percentage:

20% × 36 =

20/100 × 36720/1007.2 pounds

Weight dog trhee months ago:

36 pounds - 7.2 poundz28.8 pounds

Mathematics help ...

no links

Answers

1. 6 1/2 = 6.5. FIRST
2. 6 5/8 = 6.6. SECOND
3. 6 3/4 = 6.8. THIRD

Step-by-step explanation:

The first one is [tex]6 \frac{1}{2} [/tex]

2nd is [tex]6 \frac{5}{8} [/tex]

3rd is [tex]6 \frac{3}{4} [/tex]

There are 145 students at a small school and 41 of them are freshman. What fraction of the students are freshman

Answers

Answer: 41/145

Step-by-step explanation:

Freshmen/Total students = 41/145

Janet is 33.3% finished with
her math homework. If she
has 24 questions, how many
does she have left to finish?

Answers

7.9 questions left (not sure about this answer but I hope it’s right)

HELP 100 POINTS ASAP !!!!

Answers

Answer:

  3/2

Step-by-step explanation:

The composition of transformations has you dilate the line by a factor of 1/2, then by a factor of 3. Then the line is rotated about the origin.

The scale factor of the result will be the product of the dilation factors:

  (3)(1/2) = 3/2

The scale factor of the transformation is 3/2.

Answer:

3/2

Step-by-step explanation:

The composition of transformations has you dilate the line by a factor of 1/2, then by a factor of 3. Then the line is rotated about the origin.

The scale factor of the result will be the product of the dilation factors:

 (3)(1/2) = 3/2

The scale factor of the transformation is 3/2.

Describe the slope of the line
Find the slope.

Answers

Use equation (y2-y1)/(x2-x1)
(3-(-1))/(0-5)
4/-5 is the slope

find the sum (6a)/(a^(2)-6a+9)+(9)/(a^(2)-2a-3)

Answers

Answer:

Step-by-step explanation:

[tex]\frac{6a}{a^2-6a+9}}+\frac{9}{a^2-2a-3)}\\\\=\frac{6a}{(a-3)^2}+\frac{9}{(a-3)(a+1)}\\\\\\[/tex]

[tex]=\frac{6a(a+1)+9(a-3)}{(a-3)^2(a+1)}\\\\=\frac{6a^2+6a+9a-27}{(a-3)^2(a+1)}\\[/tex]

[tex]=\frac{6a^2+15a-27}{(a-3)^2(a+1)}\\\\=\frac{3(2a^2+5a-9)}{(a-3)^2(a+1)}[/tex]

What is the volume of the right rectangular prism below?

Answers

Answer:

C

Step-by-step explanation:

2 in. x 1 1/4 in. x 1 1/2 in. = 2/1 in. x 5/4 in. x 3/2 in. = 30/8 cubic inches =                 3 6/8 = 3 3/4 cubic inches

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