Answer:
v = 0.99 c = 2.99 x 10⁸ m/s
Explanation:
From the special theory of relativity:
[tex]t = \frac{t_o}{\sqrt{1-\frac{v^2}{c^2} } }\\[/tex]
where,
v = speed of travel = ?
c = speed of light = 3 x 10⁸ m/s
t = time measured on earth = 90 years
t₀ = time measured in moving frame = 6 months = 0.5 year
Therefore,
[tex]90\ yr = \frac{0.5\ yr}{\sqrt{1-\frac{v^2}{c^2} } } \\\\\\\sqrt{1-\frac{v^2}{c^2}} = \frac{0.5\ yr}{90\ yr}\\ 1-\frac{v^2}{c^2} = 0.00003086\\\frac{v^2}{c^2} = 1-0.00003086\\[/tex]
v = 0.99 c = 2.99 x 10⁸ m/s
Which of these properties of light is a constant?
speed in a vacuum
amplitude
wavelength
frequency
Answer:
speed in vacuum
Explanation:
lets say we are in an empty universe and you are moving 10% the speed of light you wont slow down or speed up.
Which type of diffraction occurs when the point source and the screen are at finite distances from the obstacle forming the diffraction pattern?
A. fraunhofer
B. fresnel
C. far-field
D. single slit
Infrared radiation from young stars can pass through the heavy dust clouds surrounding them, allowing astronomers here on Earth to study the earliest stages of star formation, before a star begins to emit visible light. Suppose an infrared telescope is tuned to detect infrared radiation with a frequency of 1.61THz. Calculate the wavelength of the infrared radiation. Round your answer to 3 significant digits.
Answer:
λ = 1.86 x 10⁻⁴ m = 186 μm
Explanation:
The relationship between the wavelength and the frequency of a wave is given by the following equation:
[tex]c = f\lambda\\\\\lambda = \frac{c}{f}[/tex]
where,
λ = wavelength of infrared radiation = ?
c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s
f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz
Therefore,
[tex]\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}[/tex]
λ = 1.86 x 10⁻⁴ m = 186 μm
The environment of Ecology is made up of how many levels?
Answer:
There are 5 general layers; organism, population, community, ecosystem, and biosphere.
Explanation:
Hope this helps!
1) A speaker vibrates at a frequency of 2500 Hz. What is its period?
2) A swing has a period of 15 seconds. What is its frequency?
Please help, thank you!
It's easier for you to solve these than to try and read my solutions if I solve them.
Use this magic formula:
(period) · (frequency) = 1
If you handle the magic formula carefully and correctly, you can get these facts out of it:
-- Period = 1 / frequency
-- Frequency = 1 / period
Use the first one to solve #1.
Use the second one to solve #2.
The surface of the paper is phosphorescent. When light shines on it, some of the energy is absorbed and re-emitted slowly over time. The blue LED causes the surface to glow, but the green LED does not. Would a red LED to cause the surface to glow? Select the best answer from the choices provided. View Available Hint(s) Select the best answer from the choices provided. No Yes
Answer:
No
Explanation:
Recall that the hierarchy of wavelength color from minimum wavelength to maximum wavelength is:
[tex]V < I < B < G < Y < O < R;[/tex] and
[tex]E \ \alpha \ \dfrac{1}{\lambda}[/tex]
As a result, blue light has a higher energy level than green and red light.
As a result, the surface glows due to the blue LED. The green LED, on the other hand, would not allow the surface to glow as much as the red LED, which has a lower energy level when compared to the green light. As a result, the red LED would not allow the surface to glow as well.
Object X of mass 4 kg travels with a speed of 3 ms toward object Y of mass 2 kg that is initially at rest. Object X then collides with and sticks to object Y . After the collision, object X and object Y remain stuck together. How much mechanical energy is converted into nonmechanical energy during the collision?
The nonmechanical energy or the loss of energy after the collision will be equal to [tex]E=6\ J[/tex]
What is the conservation of momentum?The conservation of the momentum is defined as when two bodies collide with each other then the total energy of the masses will remain constant.
It is given in the question that
Mass of the body X is [tex]M_X=4\ kg[/tex]
The velocity of the body X is =[tex]V_x=3 \ \frac{m}{s}[/tex]
Mass of the body Y is [tex]M_Y= 2\ kg[/tex]
The velocity of body Y is [tex]V_y= 0[/tex]
Now to find out the energy converted after the collision we will first find the final velocity of both the bodies.
Now from the conservation of the momentum
[tex]M_X V_X +M_YV_Y=(M_X+M_Y)V_F[/tex]
[tex](4\times 3)+(2\times0)=(4+2)\times V_F[/tex]
[tex]V_F= \dfrac{12}{6}[/tex]
[tex]V_F = 2 \frac{m}{s}[/tex]
Now to find the Change in the energy of the body
[tex]\Delta E=E_i-E_f[/tex]
[tex]\Delta E=\dfrac{1}{2} M_XV_X^2+\dfrac{1}{2} M_YV_Y^2-\dfrac{1}{2} (M_X+M_Y)V_F^2[/tex]
[tex]\Delta E=\dfrac{1}{2} (4)(3^2)+\dfrac{1}{2} (2)(0^2)-\dfrac{1}{2} ( 4+2) 2^2[/tex]
[tex]\Delta E= 6\ J[/tex]
Thus the nonmechanical energy or the loss of energy after the collision will be equal to [tex]E=6\ J[/tex]
To know more about the collision follow
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please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING
Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.
A) 117°
B) 88.1°
C) 26.6°
D) 30.0°
E) 45.2°
Answer:
C) 26.6
Explanation:
I don't know how to calculate vector
The angle between the two vectors is 117⁰
The given parameters;
vector A = 3.00i + 1.00j
vector B = -3.00i + 3.00j
The angle between the two vectors is calculated as follows;
[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]
The dot product of vector A and B is calculated as;
[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]
The magnitude of vector A and B is calculated as;
[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]
The angle between the two vectors is calculated as;
[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]
Thus, the angle between the two vectors is 117⁰
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Another word for kinetic energy
could be
energy.
A. Safe
B. Moving
C. Stored
D. Potential
Answer:
moving
Explanation:
hope it helped!!!
Answer:
B
Explanation:
What is the difference between center of mass and center of gravity?
Answer:
Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.
Answer:
Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field.
Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.
hope this helps you ☺️☺️
X-rays are electromagnetic waves used to obtain images of bones. An x-ray machine produces x-ray waves with a frequency of 1.25 x 10^18 Hz.
(a) Calculate the time period of these x-rays.
Answer:
[tex]T=8\times 10^{-19}\ s[/tex]
Explanation:
Given that,
The frequency of x-ray is, [tex]f=1.25\times 10^{18}\ Hz[/tex]
We need to find the time period of these x-rays. Let it is be T. We know that, the relation between f and T is given by :
T = 1/f
So,
[tex]T=\dfrac{1}{1.25\times 10^{18}}\\\\=8\times 10^{-19}\ s[/tex]
So, the time period of these x-rays is equal to [tex]8\times 10^{-19}\ s[/tex].
The time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
Given the data in the question;
Frequency; [tex]f =1.25 * 10^{18}Hz[/tex]
Time period; [tex]T =\ ?[/tex]
Time period is simply the time taken for one complete cycle of vibration to pass a given point.
It is expressed as:
[tex]T = \frac{1}{f}[/tex]
We substitute our value into the equation
[tex]T = \frac{1}{1.25 * 10^{18}Hz} \\\\T = \frac{1}{1.25 * 10^{18}s^{-1}}\\\\T = 8.0 * 10^{-19}s[/tex]
Therefore, the time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
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what happen when you take off your clothes very quickly
Answer:
Nothing
Explain
Nothing happenes when you take off your cloths quickly.
Scientificly nothing really happnes.
A student is giving a presentation to a class describing magnetic and electric fields in a region of space. First, the student describes what happens when there is a constant magnetic field in the region of space. Then, the student describes what happens when there is a time-dependent magnetic field in the region of space. Which of the following a correct description by the student abo what occurs when the magnetic field changes from being constant to being time dependent?
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
b. When the magnetic field is constant, there will be both a magnetic field and an electric field in the region of space. When the magnetic field is time dependent, there is only a magnetic field in the region of space.
с. In both situations, there will be both a magnetic field and an electric field in the region of space. In both situations, there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, then there will be both a magnetic field and an electric field in the region of space
d. In both situations there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, there will still be only a magnetic field in the region of space.
Answer:
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
Explanation:
This is true because according to Maxwell's equation, a time dependent magnetic field produces an electric field.
When the magnetic field is constant, there is no electric field in that region of space. But, when it begins to vary, an electric field is then generated by Maxwell's equation which is given by
CurlE = -dB/dt
So, there is initially no electric field when the magnetic field is constant, but it exists when the magnetic field becomes time dependent.
So when dB/dt = 0
CurlE = 0 ⇒ E = 0
So when dB/dt ≠ 0
CurlE ≠ 0 ⇒ E ≠ 0
Two vectors have magnitudes 3 and 4 . how are the directions of the two vectors related if: a/the sum has magnitude 7.0
Which of the following best describes Earth's crust, according to the theory of plate tectonics?
Answer:
the Earth's crust is broken into about 12 plates that float on hotter, softer rocks in the underlying mantle
Explanation:
An airplane flew from San Francisco to Washington, D.C. Approximately
halfway through the flight, the plane had traveled 2,000 km in 2.5 hours.
What was the speed during this period?
Another airplane is flying in the opposite direction. It covers the same distance in exactly 2 hours. What was its speed and direction during this period?
Answer:
The solution is given below:
Explanation:
The computation of the speed is shown below
As we know that
Speed = distance ÷ time
where
distance is 2000 km
And, the time is 2.5 hours
SO, the speed is
= 2,000 ÷ 2.5
= 800 km/h
Now the distance would be the same i.e. 2,000 km
but the time is 2 hours
So, the speed is
= 2,000 km ÷ 2 hours
= 1,000 km/hr
The direction should be opposite to the first airplane
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Calculate the decay constant of the radioisotope.
Answer: [tex]0.0353\ s^{-1}[/tex]
Explanation:
Given
Radioactive material is found to decrease 40% of its original value in [tex]2.59\times 10\ s[/tex]
Sample at any time is given by
[tex]N=N_oe^{-\lambda t}[/tex]
where, [tex]\lambda=\text{decay constant}[/tex]
Put values
[tex]\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10[/tex]
Taking natural logarithm both side
[tex]\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}[/tex]
Types of telescope
for Space
observation
Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.
Answer:
oii me manda mensagem fofo vc tem namorada fofo
Can someone make a list of 10 simple things people can do to maintain fitness ? Or don’t list a lot
Answer:
1. sleep well
2. drink water
3. eat healthy
4. less sugar and salt
5. exercise 30 minutes daily
6. eat whole grains
7. eat fruits and vegetables
8. practice mental health
9. stay motivated
10. eat a variety of foods
A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.
Answer:
The thickness of the oil slick. t = 173.91 nm
Explanation:
Oil film thickness t is given by the equation
[tex]t = \frac{\lambda}{2n}[/tex]
where λ = wavelength of incident light in air = 400 nm
and n = index of refraction of oil
therefore,
[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]
The thickness of the oil slick. t = 173.91 nm
The speed of sound is about 343 m/s . The wavelengths humans can hear range from .0017 m/cycle to 17m/cycle . What is the range of frequencies we can hear? Please help me !
Answer:
Explanation:
wavespeed = wavelength * frequency
wavespeed / wavelength = frequency
343 / 17 = 20.17 Hz
343 / 0.017 = 201764 Hz
So range of frequencies we can hear is between 20Hz and 20,000 Hz ( or 20.17 to 201764 if you dont round up/down)
Two window washers, Bob and Joe, are on a 3.00 m long, 395 N scaffold supported by two cables attached to its ends. Bob weighs 805 N and stands 1.00 m from the left end. Two meters from the left end is the 500 N washing equipment. Joe is 0.500 m from the right end and weighs 820 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable
Answer:
- the forces on the left hand side is 1.038 kN
- the forces on the right hand side is 1.483 kN
Explanation:
Given the data in the question, as illustrated in the image below;
Length of the scaffold = 3 m
weight of the scaffold = 395 N
Weight of Bob = 805 N and stands 1 m from the left end
weight of washing equipment = 500N and on sits 2 m from the left end
Weight of Joe = 820 N and stand 0.500 m from the right end
so the force on the left cable will be;
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ (805 N)( (3-1) m) + ( 395 N )( [tex]\frac{3}{2} m[/tex]) + ( 500 N )(1m ) + ( 820 N)( 0.500m ) ]
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ 1610 + 592.5 + 500 + 410 ]
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ 3112.5 ]
[tex]T_{left[/tex] = 1037.5 N
[tex]T_{left[/tex] = 1.038 kN
Therefore, the forces on the left hand side is 1.038 kN
On the right hand side;
[tex]T_{Right[/tex] = ( 805 N + 395 N + 500 N + 820 N ) - 1037.5 N
[tex]T_{Right[/tex] = 2520 N - 1037.5 N
[tex]T_{Right[/tex] = 1482.5 N
[tex]T_{Right[/tex] = 1.483 kN
Therefore, the forces on the right hand side is 1.483 kN
[3]2] Resistors X and Y are connected in series with a 6.0 V battery of negligible intemal
resistance.
R
X has resistance R and Y has resistance > .
A voltmeter of resistance R is connected across Y.
x
6ov |
Y
h
What is the reading on the voltmeter?
[1 mark]
A00V [Le]
B15V [e]
C 3.0V [=]
D45V fe] \
Using ohm's law and the characteristics of series and parallel circuits, we find that the correct answer is B: Voltage on the voltmeter 1.5 V
given parameters
* The element X has a resistance Rₓ = R
* Element Y with resistance R_y = R / 2
* The voltmeter with internal resistance R_v = R
* Battery voltage V = 6V
* the circuit is in the diagram
To find
The Voltmeter reading.
For this exercise we use ohm's law which establishes a linear relationship between voltage and current
V = i R
Let's solve the circuit in parts:
1 part. We reduce the part in parallel, finding its equivalent resistance
R_ {eq1}
The equivalent resistance between Y element and the voltmeter that is in parallel, therefore their equivalent resistance is
[tex]\frac{1}{R_{eq1} } = \frac{1}{R_y} + \frac{1}{R_v}[/tex]
[tex]\frac{1}{R_{eq1} }= \frac{1}{\frac{R}{2} } + \frac{1}{R} = \frac{3}{R}[/tex]
[tex]R_{eq1} = \frac{R}{3}[/tex]
Now element X and this equivalent resistance are in series ( see attached), so the equivalent resistance of the entire circuit is
R_{eq} = Rₓ + R_{eq1}
we substitute
R_{eq} = [tex]R + \frac{R}{3} = \frac{4}{3} \ R[/tex]
2 part. We look for the current of the circuit, usin the ohm's Law
V = i R_{eq}
i = [tex]\frac{V}{R_{eq} }[/tex]
i = [tex]\frac{6}{\frac{4R}{3} } = \frac{18}{4R}[/tex]
i = 4.5 / R
In a series circuit the current is constant and the total voltage is the sum voltage of each element, so the voltage in the parallel R_{eq1}
V₂ = I R_{eq1}
V₂ = [tex]\frac{4.5}{R} \ \frac{R}{3}[/tex]4.5 / R R / 3
V₂ = 1.5 V
3 part. The voltmeter and the Y element are in parallel, so the voltage in the two elects is the same, consequently the voltage of the voltmeter (V_v)
V_v = V₂ = 1.5 V
Using ohm's law and the properties of series and parellel circuits we find the voltage across the voltmeter
V_v = 1.5 V
To learn about series and parallel circuits here: brainly.com/question/11409042
What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?
0 1 = 0.01 A
0 1 = 0.8 A
0 1 = 80 A
O I = 0.08 A
Answer:
80 A
Explanation:
Hi there!
Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I
[tex]V=IR\\0.8=I(0.01)[/tex]
Divide both sides by 0.01 to isolate I
[tex]0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I[/tex]
Therefore, the current for this circuit would be 80 A.
I hope this helps!
please answer this im not sure
Answer:
the answer is B
helpppppppppppppppppppppppppppp............
an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.
Answer:
0.5 m/s 2 is the acceleration
Explanation:
hope it helped!!!
In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- vestigated occurs when the external field Bext has magnitude 0.78 T. Assume that Bint and Bext are in the same direction and take the pro- ton magnetic moment component u, to be 1.41 X 10-26 J/T. What is the magnitude of Bint?
Answer:
[tex]B_{int}=-0.015T[/tex]
Explanation:
From the question we are told that:
RF source oscillation speed [tex]\sigma= 34 MHz[/tex]
The external field [tex]Bext =0.78 T[/tex].
Pro- ton magnetic moment component [tex]\mu=1.41 X 10-26 J/T[/tex]
Generally the equation for magnitude of [tex]B_{int}[/tex] is mathematically given by
[tex]B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}[/tex]
[tex]B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}[/tex]
[tex]B_{int}=0.78-0.7957[/tex]
[tex]B_{int}=-0.015T[/tex]
A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is
the KE of the student at the bottom of the slide?
Answer:
https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html
Explanation:
One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) technique. As corn photosynthesizes, it concentrates the isotope carbon-13, whereas most other plants concentrate carbon-12. Overreliance on corn consumption can then be correlated with certain diseases, because corn lacks the essential amino acid lysine. Archaeologists use a mass spectrometer to separate the 12 C and 13 C isotopes in samples of human remains. Suppose you use a velocity selector to obtain singly ionized (missing one electron) atoms of speed 8.50 km/s, and you want to bend them within a uniform magnetic field in a semicircle of diameter 25.0 cm for the 12 C. The measured masses of these isotopes are 1.99×10−26kg(12C) and 2.16×10−26kg(13C).
(a) What strength of magnetic field is required?
(b) What is the diameter of the 13 C semicircle?
(c) What is the separation of the 12 C and 13 C ions at the detector at the end of the semicircle? Is this distance large enough to be easily observed?
Answer:
[tex]0.0084575\ \text{T}[/tex]
[tex]0.272\ \text{m}[/tex]
2.2 cm easily observable
Explanation:
[tex]m_1[/tex] = Mass of 12 C = [tex]1.99\times 10^{-26}\ \text{kg}[/tex]
[tex]m_2[/tex] = Mass of 13 C = [tex]2.16\times 10^{-26}\ \text{kg}[/tex]
[tex]r_1[/tex] = Radius of 12 C = [tex]\dfrac{25}{2}=12.5\ \text{cm}[/tex]
B = Magnetic field
v = Velocity of atom = 8.5 km/s
[tex]r_2[/tex] = Radius of 13 C
The force balance of the system is
[tex]qvB=\dfrac{m_1v^2}{r}\\\Rightarrow B=\dfrac{m_1v}{rq}\\\Rightarrow B=\dfrac{1.99\times 10^{-26}\times 8500}{12.5\times 10^{-2}\times 1.6\times 10^{-19}}\\\Rightarrow B=0.0084575\ \text{T}[/tex]
The required magnetic field is [tex]0.0084575\ \text{T}[/tex]
Radius is given by
[tex]r=\dfrac{mv}{qB}[/tex]
[tex]r\propto m[/tex]
So
[tex]\dfrac{r_2}{r_1}=\dfrac{m_2}{m_1}\\\Rightarrow r_2=\dfrac{m_2}{m_1}r_1\\\Rightarrow r_2=\dfrac{2.16\times 10^{-26}}{1.99\times 10^{-26}}\times 12.5\times 10^{-2}\\\Rightarrow r_2=0.136\ \text{m}[/tex]
The required diameter is [tex]2\times 0.136=0.272\ \text{m}[/tex]
Separation is given by
[tex]2(r_2-r_1)=2(0.136-0.125)=0.022\ \text{m}[/tex]
The distance of separation is 2.2 cm which is easily observable.