The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.
Answers
The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
v = v₀ + a t
y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
v = v₀ + a t
[tex]a = \frac{v-v_o}{\Delta t}[/tex]
[tex]a = \frac{2-0}{8-0}[/tex]
a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
[tex]a = \frac{6-2}{ 14-10}[/tex]
a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
[tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]
We look for every displacement.
d₁ = v₀ + ½ a₁ Δt²
d₁ = 0 + ½ 0.25 8²
d₁ = 8 m
In the second section the velocity is constant
d₂ = v₂ Δt₂
d₂ = 2 (10-8)
d₂ = 4 m
The third section.
d₃ = v₀ + ½ a t²
d₃ = 2 + ½ 1 (14-10) ²
d₃ = 10 m
The distance of the fourth section.
we look for acceleration
a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]
a₄ = [tex]\frac{0-6}{18-14}[/tex]
a₄ = -1.5 m / s²
d₄ = 6 + ½ (-1.5) (1814) ²
d₄ = -6 m
The total displacement is;
[tex]d_{total}[/tex] = 8 + 4 + 10 -6
[tex]d_{total}[/tex] = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
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mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.
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It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.
Explanation:
which technique of extrasolar planet detection can tell us about the orbital period of a planet?
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A planet's distance from the sun will not be the same in six months.
A planet's speed as it moves around the sun will not be the same in six months.
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option is the answer
A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
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r is 2m
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Identify the class of lever whch is not used for lifting heavy loads but as used for making work faster. Explain your answer.
Answers
Answer:
3 class lever .
Explanation:
Third class lever: In the third class lever, the effort is located in between fulcrum and load. Here, effort arm is shorter than the load arm. It cannot lift the heavy load but increases the speed of doing work. ............. can you me as brainlist pls
Help it’s multiple choice 11 through 15 please!
Answers
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Two lumps of clay approach each other from opposite directions and collide head on inelastically, combing into one large lump after they collide. the first lump has a mass of 0.140kg and has a speed of 3.50 m/s before the Collision. the second lump has a mass of 0.620kg and has a speed of 4.81 m/s before the collison in a direction opposite that of the first lump. what velocity does the combined lump have after the collision?
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Answer:
Before collision:
momentum to right = .14 * 3.5 = .49 kg m / s
momentum to left = .62 * 4.81 = 2.98 kg m / s
Total momentum = .49 - 2.98 = - 2.49 to left
M V = -2.49 net momentum to left
V = -2.49 / (.14 + .62) = -3.28 m/s to left
how does cells and tissues work together with the brain to do its job
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describe the working principle of a hydraulic press using pascals principle
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Answer:
A hydraulic press works on the principle of Pascal's law, which states that when pressure is applied to a confined fluid, the pressure change occurs throughout the entire fluid. Within the hydraulic press, there is a piston that works as a pump, that provides a modest mechanical force to a small area of the sample.
Explanation:
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9
Answers
Answer:
5)
Solution
initial velocity = 15 m/s
acceleration = 3m/s^2
time = 4 s
final velocity = 15+3×4
=15+12
=27m/s
A car accelerates from 20m/s to 30m/s in 10 second
T9 be honest I think some part of the second question is missing
4. In not less than 150 words, write your substantial insights on what you have learned in the past modules in relevance to what is happening now.
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Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
Hope this helps !!Situation You are going through a very rough time. You feel so down that you need someone to talk to you send a text message to your friend asking her if she could come over to make you feel better. You friend gives you a call then tells you she will be there in 20 minutes. You are so happy to see her, you give her a big hug. then pour your heart out. After crying to her for a good 30 minutes. she gives some comforting words. You finally say that you feel so much better. Your mend then says. "That's good to know. Now we're done, could we settle my expenses for this - 20 pesos for the phone call, 35 pesos for the tricycle nde going to your place, 20 pesos for all the tissue paper you drew from my tissue pack, and 10 pesos for the time I lost to working productively because had to come here. Thanks." What would be your reaction to your friend after she says this? Fourreaction
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Answer:
she is your bestfriend so she should always be there for you as long as you are there for them but be like omg im so sorry.
Explanation:
wow tea is pouring
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answers
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
_____
Additional comment
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
Help me as soon as possible <3
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Answer: ??? what the
Explanation:
about conserving and protecting our coral reefs. 3. Punch a hole and put ribbon or string on it. Rubrics will serve as your guide in creating your bookmark. (SAMPLE BELOW) Protect Keep it our clean! Corals! de Questions: 1. What was your awareness message all about in your bookmark? 5. Do you believe there is a need to protect our coral reefs after doing this activity? Why? The Tubbataha Reef in Palawan is our country's pride. It is one of UNESCO World Heritage Sites. What would you suggest our government do to protect this?
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The above question requires a personal answer about your perception of corals, environmental conservation, and the activity you did in the classroom. In that case, I can't answer your question, but I'll show you how to answer it.
Please consider the following information to answer your questions:
The awareness message about corals refers to their preservation, due to their environmental and economic importance.After doing your activity you should be able to understand the importance of preserving corals. That's because they are important for fish spawning and habitat, blocking wave erosion, and protecting coastal communities.To protect coral reefs, the government must map reef areas, reduce marine pollution, monitor fish exploitation, protect coral areas and encourage environmental education and awareness of nature conservation.In summary, coral reefs must be protected so that the natural marine balance is maintained.
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A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?
Have a great day!
Answers
Answer:
1176.798 J
Explanation:
[] Use the following equation:
U = mgh
m - mass
g - gravitational field
h - height
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
how do you find average velocity (average) from acceleration) and time (t)?
Answers
Average velocity is defined as the ratio in change in position to change in time,
v[ave] = ∆x/∆t
which on its own doesn't have anything to do with acceleration.
If acceleration is constant, the average velocity is the literal average of the initial and final velocities,
v[ave] = (v[final] + v[initial]) / 2
If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by
v[final] = v[initial] + a*t
and plugging this into the previous equation gives
v[ave] = (v[initial] + a*t + v[initial])/2
v[ave] = v[initial] + 1/2*a*t
If the body in consideration is initially at rest, then
v[ave] = 1/2*a*t
which might be the relation you're looking for. But bear in mind the conditions I've underlined.
If acceleration is not constant and changes over time, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then
[tex]\displaystyle v(t) = v(0) + \int_0^t a(u) \, du[/tex]
or if you know any other velocity for some time t₀ > 0,
[tex]\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du[/tex]
in any chemical reaction or physical change the mass of the product is ___ The mass of the reactant
a. The relationship cannot be determined by the amount of information given
b. equal to or the same
c. twice is greater than
d. twice as less than
Answers
Answer: b. equal to or the same
In Law of Conservation of mass, the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.
pls mark brainliest! i really need one :(
What ions are produced from acids and bases?
Answers
Answer:
Give person above me brainliest
Explanation:
please help me! i’ll mark brainliest if you’re correct!
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The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:
[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]
Answer: 3N to the right
Explanation: 2N- 5N= 3N
Block 1, of mass m1
m
1
= 0.500 kg
k
g
, is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2
m
2
, as shown. For an angle of θ
θ
= 30.0 ∘
∘
and a coefficient of kinetic friction between block 2 and the plane of μ
μ
= 0.400, an acceleration of magnitude a
a
= 0.450 m/s2
m
/
s
2
is observed for block 2.
Find the mass of block 2, m2
m
2
.
Answers
Answer:
M2=0.52kg
Explanation:
thats rightt
An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground
Answers
Answer:
20 ft/sec / 32 ft/sec^2 = .625 to reach top
2 * .625 = 1.25
It will be on the ground at t = 0 and t = 1.25
You can also solve the equation:
H = 0 = V0 t - 1/2 g t^2
Obviously, at t=0 h = 0
V0 = 1/2 g t is a solution
t = 20 * 2 / 32 = 1.25 sec
A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
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Answer:
This is the answer that I got.
Explanation:
Hope it is right.
A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from point D to point E. What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio? Negative one-eleventh One-eleventh Two-fifteenths Fifteen-halves.
Answers
The location of the point F that partitions a line segment from D to E ([tex]\overline{DE}[/tex]), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at negative -4 and point E is at positive 5, we have:
[tex] \overline{DE} = E - D = 5 - (-4) = 9 [/tex]
Hence, the segment of the line DE ([tex]\overline{DE}[/tex]) is 9.
Knowing that point F partitions the line segment from D to E ([tex]\overline{DE}[/tex]) into a 5:6 ratio, its location would be:
[tex] F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2} [/tex]
Therefore, the location of point F is fifteen halves (option 4).
Learn more about segments here:
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I hope it helps you!
Answer:
The above answer is actually incorrect - the real answer is B. 1/11
Explanation:
I'm adding a ss below for proof
Hope this helped!
I'd really appreciate Brainliest :)
A bullet of mass 20 g has its kinetic energy equal to 400 J. Find the speed of the bullet.
Answers
Answer:
m=20g=0.02kgK.E=400J[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}(0.02)v^2=400[/tex]
[tex]\\ \sf\longmapsto 0.01v^2=400[/tex]
[tex]\\ \sf\longmapsto v^2=40000[/tex]
[tex]\\ \sf\longmapsto v=200m/s[/tex]
A racing car has a mass of 750 kg. It undergoes an acceleration of 4.00 m/s2. What is the net force acting on the car?
Answers
Answer:
3000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 750 × 4 = 3000
We have the final answer as
3000 NHope this helps you
Was there any angle given with the question
Answers
Answer:
No.
Explanation:
In the question, no mathematical angle is shown.
18 through 22 multiple choice please help
Answers
Answer:
18:equilibrium
19:10.8
20:separating the surfaces with a layer of air
21:it remains motionless
22:cm/s
i. la protagonista ama a su gata. escribimos, en nuestros cuadernos , las razones por las que pensamos que las personas aman de manera exagerada a sus mascotas. Proponemos un antídoto para la soledad. Lo escribrimos
Answers
Las mascotas son una buena fuente de compañía y socias en la soledad.
La protagonista ama a su gato porque las mascotas son una buena fuente de compañía y es un antídoto para la soledad. Estas mascotas como perros, gatos, loros, etc. dan placer y felicidad a las personas.
La gente tiene mascotas para pasar tiempo con ellas y jugar con ellas para refrescar sus mentes. Tener mascotas es una actividad maravillosa que hace que nuestra mente esté relajada y llena de felicidad, por lo que podemos concluir que las mascotas son una buena fuente de compañía y compañera en la soledad.
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40 POINTSS. Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fingertip. Note how much opposition to your push you feel. Repeat the steps, but this time push the piece of plastic or wood across a rug, carpet, or piece of fabric. If you’re using fabric, be sure to secure the fabric so it doesn’t move. How does the opposition to motion on the tabletop compare with that of the rug, carpet, or fabric? WILL MARK BRAINLIST IF RIGHT
Answers
Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.