Answer:
[tex]3 \times 10 {}^6[/tex]
Another word for kinetic energy
could be
energy.
A. Safe
B. Moving
C. Stored
D. Potential
Answer:
moving
Explanation:
hope it helped!!!
Answer:
B
Explanation:
Infrared radiation from young stars can pass through the heavy dust clouds surrounding them, allowing astronomers here on Earth to study the earliest stages of star formation, before a star begins to emit visible light. Suppose an infrared telescope is tuned to detect infrared radiation with a frequency of 1.61THz. Calculate the wavelength of the infrared radiation. Round your answer to 3 significant digits.
Answer:
λ = 1.86 x 10⁻⁴ m = 186 μm
Explanation:
The relationship between the wavelength and the frequency of a wave is given by the following equation:
[tex]c = f\lambda\\\\\lambda = \frac{c}{f}[/tex]
where,
λ = wavelength of infrared radiation = ?
c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s
f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz
Therefore,
[tex]\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}[/tex]
λ = 1.86 x 10⁻⁴ m = 186 μm
Which type of diffraction occurs when the point source and the screen are at finite distances from the obstacle forming the diffraction pattern?
A. fraunhofer
B. fresnel
C. far-field
D. single slit
what happen when you take off your clothes very quickly
Answer:
Nothing
Explain
Nothing happenes when you take off your cloths quickly.
Scientificly nothing really happnes.
helpppppppppppppppppppppppppppp............
an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.
Answer:
0.5 m/s 2 is the acceleration
Explanation:
hope it helped!!!
Can someone make a list of 10 simple things people can do to maintain fitness ? Or don’t list a lot
Answer:
1. sleep well
2. drink water
3. eat healthy
4. less sugar and salt
5. exercise 30 minutes daily
6. eat whole grains
7. eat fruits and vegetables
8. practice mental health
9. stay motivated
10. eat a variety of foods
Two window washers, Bob and Joe, are on a 3.00 m long, 395 N scaffold supported by two cables attached to its ends. Bob weighs 805 N and stands 1.00 m from the left end. Two meters from the left end is the 500 N washing equipment. Joe is 0.500 m from the right end and weighs 820 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable
Answer:
- the forces on the left hand side is 1.038 kN
- the forces on the right hand side is 1.483 kN
Explanation:
Given the data in the question, as illustrated in the image below;
Length of the scaffold = 3 m
weight of the scaffold = 395 N
Weight of Bob = 805 N and stands 1 m from the left end
weight of washing equipment = 500N and on sits 2 m from the left end
Weight of Joe = 820 N and stand 0.500 m from the right end
so the force on the left cable will be;
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ (805 N)( (3-1) m) + ( 395 N )( [tex]\frac{3}{2} m[/tex]) + ( 500 N )(1m ) + ( 820 N)( 0.500m ) ]
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ 1610 + 592.5 + 500 + 410 ]
[tex]T_{left[/tex] = [tex]\frac{1}{3m}[/tex][ 3112.5 ]
[tex]T_{left[/tex] = 1037.5 N
[tex]T_{left[/tex] = 1.038 kN
Therefore, the forces on the left hand side is 1.038 kN
On the right hand side;
[tex]T_{Right[/tex] = ( 805 N + 395 N + 500 N + 820 N ) - 1037.5 N
[tex]T_{Right[/tex] = 2520 N - 1037.5 N
[tex]T_{Right[/tex] = 1482.5 N
[tex]T_{Right[/tex] = 1.483 kN
Therefore, the forces on the right hand side is 1.483 kN
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Calculate the decay constant of the radioisotope.
Answer: [tex]0.0353\ s^{-1}[/tex]
Explanation:
Given
Radioactive material is found to decrease 40% of its original value in [tex]2.59\times 10\ s[/tex]
Sample at any time is given by
[tex]N=N_oe^{-\lambda t}[/tex]
where, [tex]\lambda=\text{decay constant}[/tex]
Put values
[tex]\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10[/tex]
Taking natural logarithm both side
[tex]\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}[/tex]
Types of telescope
for Space
observation
Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.
Answer:
oii me manda mensagem fofo vc tem namorada fofo
Two vectors have magnitudes 3 and 4 . how are the directions of the two vectors related if: a/the sum has magnitude 7.0
A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.
Answer:
The thickness of the oil slick. t = 173.91 nm
Explanation:
Oil film thickness t is given by the equation
[tex]t = \frac{\lambda}{2n}[/tex]
where λ = wavelength of incident light in air = 400 nm
and n = index of refraction of oil
therefore,
[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]
The thickness of the oil slick. t = 173.91 nm
One method for determining the amount of corn in early Native American diets is the stable isotope ratio analysis (SIRA) technique. As corn photosynthesizes, it concentrates the isotope carbon-13, whereas most other plants concentrate carbon-12. Overreliance on corn consumption can then be correlated with certain diseases, because corn lacks the essential amino acid lysine. Archaeologists use a mass spectrometer to separate the 12 C and 13 C isotopes in samples of human remains. Suppose you use a velocity selector to obtain singly ionized (missing one electron) atoms of speed 8.50 km/s, and you want to bend them within a uniform magnetic field in a semicircle of diameter 25.0 cm for the 12 C. The measured masses of these isotopes are 1.99×10−26kg(12C) and 2.16×10−26kg(13C).
(a) What strength of magnetic field is required?
(b) What is the diameter of the 13 C semicircle?
(c) What is the separation of the 12 C and 13 C ions at the detector at the end of the semicircle? Is this distance large enough to be easily observed?
Answer:
[tex]0.0084575\ \text{T}[/tex]
[tex]0.272\ \text{m}[/tex]
2.2 cm easily observable
Explanation:
[tex]m_1[/tex] = Mass of 12 C = [tex]1.99\times 10^{-26}\ \text{kg}[/tex]
[tex]m_2[/tex] = Mass of 13 C = [tex]2.16\times 10^{-26}\ \text{kg}[/tex]
[tex]r_1[/tex] = Radius of 12 C = [tex]\dfrac{25}{2}=12.5\ \text{cm}[/tex]
B = Magnetic field
v = Velocity of atom = 8.5 km/s
[tex]r_2[/tex] = Radius of 13 C
The force balance of the system is
[tex]qvB=\dfrac{m_1v^2}{r}\\\Rightarrow B=\dfrac{m_1v}{rq}\\\Rightarrow B=\dfrac{1.99\times 10^{-26}\times 8500}{12.5\times 10^{-2}\times 1.6\times 10^{-19}}\\\Rightarrow B=0.0084575\ \text{T}[/tex]
The required magnetic field is [tex]0.0084575\ \text{T}[/tex]
Radius is given by
[tex]r=\dfrac{mv}{qB}[/tex]
[tex]r\propto m[/tex]
So
[tex]\dfrac{r_2}{r_1}=\dfrac{m_2}{m_1}\\\Rightarrow r_2=\dfrac{m_2}{m_1}r_1\\\Rightarrow r_2=\dfrac{2.16\times 10^{-26}}{1.99\times 10^{-26}}\times 12.5\times 10^{-2}\\\Rightarrow r_2=0.136\ \text{m}[/tex]
The required diameter is [tex]2\times 0.136=0.272\ \text{m}[/tex]
Separation is given by
[tex]2(r_2-r_1)=2(0.136-0.125)=0.022\ \text{m}[/tex]
The distance of separation is 2.2 cm which is easily observable.
please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING
X-rays are electromagnetic waves used to obtain images of bones. An x-ray machine produces x-ray waves with a frequency of 1.25 x 10^18 Hz.
(a) Calculate the time period of these x-rays.
Answer:
[tex]T=8\times 10^{-19}\ s[/tex]
Explanation:
Given that,
The frequency of x-ray is, [tex]f=1.25\times 10^{18}\ Hz[/tex]
We need to find the time period of these x-rays. Let it is be T. We know that, the relation between f and T is given by :
T = 1/f
So,
[tex]T=\dfrac{1}{1.25\times 10^{18}}\\\\=8\times 10^{-19}\ s[/tex]
So, the time period of these x-rays is equal to [tex]8\times 10^{-19}\ s[/tex].
The time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
Given the data in the question;
Frequency; [tex]f =1.25 * 10^{18}Hz[/tex]
Time period; [tex]T =\ ?[/tex]
Time period is simply the time taken for one complete cycle of vibration to pass a given point.
It is expressed as:
[tex]T = \frac{1}{f}[/tex]
We substitute our value into the equation
[tex]T = \frac{1}{1.25 * 10^{18}Hz} \\\\T = \frac{1}{1.25 * 10^{18}s^{-1}}\\\\T = 8.0 * 10^{-19}s[/tex]
Therefore, the time period of the electromagnetic wave is 8.0 × 10⁻¹⁹ seconds.
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An airplane flew from San Francisco to Washington, D.C. Approximately
halfway through the flight, the plane had traveled 2,000 km in 2.5 hours.
What was the speed during this period?
Another airplane is flying in the opposite direction. It covers the same distance in exactly 2 hours. What was its speed and direction during this period?
Answer:
The solution is given below:
Explanation:
The computation of the speed is shown below
As we know that
Speed = distance ÷ time
where
distance is 2000 km
And, the time is 2.5 hours
SO, the speed is
= 2,000 ÷ 2.5
= 800 km/h
Now the distance would be the same i.e. 2,000 km
but the time is 2 hours
So, the speed is
= 2,000 km ÷ 2 hours
= 1,000 km/hr
The direction should be opposite to the first airplane
According to Lenz's law, the current is induced in the closed conducting loop in such a direction that the magnetic field induced by this current opposes the change in the flux through the loop.
a. True
b. False
Answer:
True
Explanation:
It is true that the real definition of lenz's law in magnetism is the current is induced in the closed conducting loop in such a direction that the magnetic field induced by this current opposes the change in the flux through the loop.
This means that induced current opposes the very cause that produces it.
What is the difference between center of mass and center of gravity?
Answer:
Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.
Answer:
Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field.
Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.
hope this helps you ☺️☺️
Which of these properties of light is a constant?
speed in a vacuum
amplitude
wavelength
frequency
Answer:
speed in vacuum
Explanation:
lets say we are in an empty universe and you are moving 10% the speed of light you wont slow down or speed up.
please answer this im not sure
Answer:
the answer is B
What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?
0 1 = 0.01 A
0 1 = 0.8 A
0 1 = 80 A
O I = 0.08 A
Answer:
80 A
Explanation:
Hi there!
Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I
[tex]V=IR\\0.8=I(0.01)[/tex]
Divide both sides by 0.01 to isolate I
[tex]0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I[/tex]
Therefore, the current for this circuit would be 80 A.
I hope this helps!
Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.
A) 117°
B) 88.1°
C) 26.6°
D) 30.0°
E) 45.2°
Answer:
C) 26.6
Explanation:
I don't know how to calculate vector
The angle between the two vectors is 117⁰
The given parameters;
vector A = 3.00i + 1.00j
vector B = -3.00i + 3.00j
The angle between the two vectors is calculated as follows;
[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]
The dot product of vector A and B is calculated as;
[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]
The magnitude of vector A and B is calculated as;
[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]
The angle between the two vectors is calculated as;
[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]
Thus, the angle between the two vectors is 117⁰
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A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is
the KE of the student at the bottom of the slide?
Answer:
https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html
Explanation:
In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- vestigated occurs when the external field Bext has magnitude 0.78 T. Assume that Bint and Bext are in the same direction and take the pro- ton magnetic moment component u, to be 1.41 X 10-26 J/T. What is the magnitude of Bint?
Answer:
[tex]B_{int}=-0.015T[/tex]
Explanation:
From the question we are told that:
RF source oscillation speed [tex]\sigma= 34 MHz[/tex]
The external field [tex]Bext =0.78 T[/tex].
Pro- ton magnetic moment component [tex]\mu=1.41 X 10-26 J/T[/tex]
Generally the equation for magnitude of [tex]B_{int}[/tex] is mathematically given by
[tex]B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}[/tex]
[tex]B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}[/tex]
[tex]B_{int}=0.78-0.7957[/tex]
[tex]B_{int}=-0.015T[/tex]