The length of EF from the given diagram is 2.98
How to calculate the length of an arcThe formula for calculating the length of an arc is expressed as;
L = rtheta
where
r is the radius
theta is the subtended angle
Given the following
r = 7/9π
theta = 70 degrees
L = 70/360 * 2 * 7/9π * π
L = 2.98
Hence the length of EF is 2.98
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Rewrite the Equation in Ax+By=C form. Use Integers for A,B, and C
Answer:
-x + 5y = 15
Step-by-step explanation:
Hello! This question simply asks us to rearrange the equation.
So we have this:
y - 2 = 5(x + 5)
Okay, so we need to get an answer with integers for x and y, but no brackets. This means we can start by expanding them:
5y - 10 = x + 5
now, let's put y and x on the same side of the equation, and numbers on the other side:
5y - x = 5 + 10
5y - x = 15
we can put x first, but it's not necessary:
-x + 5y = 15
A = -1
B = 5
C = 15
And that's it!
I hope this makes sense :))
Answer:
5x - y = - 27
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
given
y - 2 = 5(x + 5) ← distribute parenthesis
y - 2 = 5x + 25 ( add 2 to both sides )
y = 5x + 27 ( subtract 5x from both sides )
- 5x + y = 25 ( multiply through by - 1 )
5x - y = - 27 ← in standard form
I NEED THIS DONE IN 5 MIN SOMEONE HELP
Answer:
4
Step-by-step explanation:
Question 2 of 5
A cylinder has a diameter of 10 inches and a height of 20 inches. What is the
volume of the cylinder?
А. 1000п
B. 50017
C. 200017
O D. 2001
SUBMIT
Answer
B. 500 pi
Step-by-step explanation:
A snowboarding competition site is using a new design for the parallel giant slalom. The designer of the slalom is investigating whether there is a difference in the mean times taken to complete a run for men and women competitors. As part of the investigation, independent random samples of men and women who will use the slalom run are selected and their times to complete a run are recorded. Which of the following is the appropriate inference procedure by which the designer can estimate the difference in the mean completion times for men and women?
i. A one-sample I-Interval for a sample mean e-sample interval for a population mean
ii. A matched para tantervil for a meen difference
iii. A two-sample -interval for a difference between population means
iv. A two-sample t-interval for a difference between sample means
Considering that we have two samples, and the standard deviation for each sample, the correct test is given by:
iii. A two-sample -interval for a difference between population means.
When to use a t-test and a z-test?If we have the standard deviation for the sample, the t-test is used.If we have the standard deviation for the population, a z-test is used.Here, there are two samples, and we will investigate their difference. The information taken from the sample is expanded to the population, and since we have the standard deviation for each sample, a t-test is used, hence the correct option is given by:
iii. A two-sample -interval for a difference between population means.
More can be learned about hypothesis tests at https://brainly.com/question/26454209
3. Angles X and Y have a sum of 159 degrees. Angle X is 43 degrees smaller than angle Y.
Write a system of equations that represent this, then solve it to find the measures of both
angles.
[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]
[tex]\longrightarrow[/tex]Since angle X and Y have a sum of 159
[tex]\implies \bf Y + X= 159 \_\_\_\_(1) [/tex]
[tex]\longrightarrow[/tex]Since X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -
[tex]\implies \bf Y - X = 43 \_\_\_\_(2) [/tex]
Adding Equation (1) and (2)
[tex]\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered} [/tex]
Putting Y in eq (1)
[tex]\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf X = 153-101 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \boxed{\sf{ X = 52 }}\\\end{gathered} [/tex]
Find the smallest part when £80 is
shared in the ratio 7:3
Answer:
£24
Step-by-step explanation:
= 3/(7+3) × £80
= 3/10 × £80
= £24
2. Simplify each expression into its standard
(x - 3)(6x - 2)
Answer: 6x² - 20x + 6
Step-by-step explanation:
x(6x - 2) -3(6x - 2)
= 6x² - 2x - 18x + 6
= 6x² - 20x + 6
Find f(6) if f(x) = x2 ÷ 3 + x.
18
21
10
4
Answer:
the answer for d question is 10
The perimeter of a square is equal to the perimeter of rectangle of length = 16 cm and breadth=4 cm. What is the perimeter and side of the square?
What is the overlap of Data Set 1 and Data Set 2?
high
moderate
low
none
Two line plots with the same scale and interval, from fifty two to sixty two, with tick marks every one unit. The plots are stacked vertically for comparison. Each plot has eleven data values. Values appear as x marks above the line. Upper plot data values are one x mark above fifty three, one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, and one x mark above sixty. Lower plot data values are one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, one x mark above fifty nine and one x mark above sixty.
Answer:
Well my answer is high data set I took the test and got 100%
Step-by-step explanation:
Answer:
High
Step-by-step explanation: I took the test.
3. a. Prove that A(1,1), B(4,4), C(6,2) are the vertices of a
right triangle using slopes.
Answer:
Step-by-step explanation:
A standard sheet of paper in the United States is 11 inches long and 8.5 inches wide. Each inch is 2.54 centimeters. How long and wide is a standard sheet of paper in centimeters?
A football stadium sells regular and box seating. There are twelve times as many
regular seats as there are box seats. The total capacity of the stadium is 10,413. How
many box seats are in the stadium? How many regular seats?
Answer:
There are 801 box seats and 9612 regular seats.
explanation:
Let the number of box seats be x,
Then the regular seats is 12x
The sum of seats equals to 10,413
Solve:
12x + x ➙ 10,413
13x ➙ 10413
x ➙ 801
There are 801 box seats.
Find for regular seats:
➙ 12(x)
➙ 12(801)
➙ 9612
There are 9612 regular seats.
There are 65 seats on a train. 60% of the seats are empty. How many empty seats are there
on the train?
Answer:
39 seats are empty
Step-by-step explanation:
60% of 65 is 39
Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. respectively.
Given :
The radii of the circular paths are 210 m. and 490 m.To Find :
The area of the region between two concentric circular paths.Solution :
Area of the outer circle :
[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}} [/tex]
⠀
Area of the inner circle :
[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}} [/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}} [/tex]
⠀
Therefore,
Area of the region inside the circular paths :
[tex]\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}[/tex]
[tex]\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}[/tex]
If someone can answer these both I’ll give 75 points
Solution (1):
Note that:
Sum of interior angles = 180°This means that...
5x + 3x + 2 + 130 = 180Finding the value of x.
5x + 3x + 2 + 130 = 180=> 8x + 132 = 180=> 8x = 180 - 132=> 8x = 48=> x = 6Solution (2):
Note that:
Sum of interior angles = 180°This means that...
x + 66 + x + 86 + 50 = 180°Finding the value of x.
x + 66 + x + 86 + 50 = 180°=> 2x + 202 = 180°=> 2x = -22=> x = -11the hot air popcorn maker used at the movies theater produces 14 cups of popcorn in 2.5 minutes. what is the unit rate per minute?
what is the area, please help me!
Answer:
30ft2. (C.)
I did this question once.
Sorry for my Lack of explanation.-
Answer:
C
Step-by-step explanation:
Draw a line to make 2 separate shapes and find the area of each them then add the 2 areas together
18+12=30
Look at the cards below. When the cards are face down, your chances of picking an "A" card out of the group are 2/5. Approximately how many times would you pick an "A" card if you chose 50 times? XA GAP x S Р Hint: Set up a proportion
50 times; 40% A
2/5(50) = A
A = 20
Answer:
50 times; 40% A
2/5(50) = A
A = 20
Step-by-step explanation:
How many times does 15 go into 30
Answer:
2
Step-by-step explanation:
subtract 15 from 30 till u have 0 and count how many times u subtracted 15 from 30
Answer:
2
Step-by-step explanation:
30÷15=2
so 15 goes into 30 2times
Need Help Please!!!!!!
Answer:
64°
.
.........................
97 is what percent of 837? Round to the nearest whole #
Answer:
12
Step-by-step explanation:
Can someone pls explain me how to do this pls!!!
Answer:
A, C, E
Step-by-step explanation:
You would want to graph the points an if the line goes through them then that would be the answer
high speed train travels at a speed of 200 km/h if the train sets off from station A at 12 24 and reaches station B AT 14 12 find the distance in between two stations giving your answer in meters.
Answer: 360000m
Step-by-step explanation:
Okay, so since we know that this train’s speed is 200km/h, let’s find the time difference between 12 24 and 14 12.
14 12 - 2hrs = 12 12
12 12 + 12min = 12 24
2hrs -12min = 1hr 48 min
1hr 48 min also equals to 1.8hrs in decimals. So:
200km x 1.8 = 360km
Now we have to find the answer in meters. Since 1km is equal to 1000m,
That means 360km equals 360000m.
Therefore 360000m is the answer
Normal body temperature is 98.6 degrees Fahrenheit. When Tyler had a fever, his temperature went up to 102.2 degrees. By how much did Tyler's temperature increase?
[tex]v = \frac{er}{r + a} [/tex]
Find R in image
Step-by-step explanation:
[tex]V = \frac{ER}{R + a} [/tex]
[tex]V(R+a)=ER[/tex]
[tex]VR + Va=ER[/tex]
[tex]Va= ER-VR[/tex]
[tex]Va=R(E-V)[/tex]
[tex]R = \frac{Va}{E-V} [/tex]
This figure represents a compartment in a container for storing sewing supplies. Another compartment is identical except that it is 3 centimeters taller. What is the difference in volume of the two compartments? Enter your answer in the box.
The difference in volume of the two compartments is 210 cm³
What is volume?
Volume is the amount of space occupied by a three dimensional shape or figure.
The volume of the compartment = area of base * height
Area of base (trapezoid) = (1/2)(sum of parallel side)(height) = (1/2) * (15 + 5) * (7) = 70 cm²
Volume of compartment = 70 * 8 = 560 cm³
For the new compartment, height = 8 + 3 = 11 cm, hence:
Volume of new compartment = 70 * 11 = 770 cm³
Difference in volume = 770 cm³ - 560 cm³ = 210 cm³
The difference in volume of the two compartments is 210 cm³
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Answer: 210 because I got it correct on the k12.
Step-by-step explanation:
Solve for x and y
2x-5y=1, 3x+2y=11
2x - 5y = 1
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.
[tex]\rm{2x - 5y = 1 }\\ [/tex]
[tex] \rm{2x - 5y + 5y = 1 + 5y}\\[/tex]
Subtract -5y from both sides of the equation
Simplify 2x - 5y + 5y = 1 + 5y
Cancel -5y with 5y
Reorder 1 + 5y so highest order terms are first
[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]
Move factors not having X from the left side of equation 2x = 5y + 1
[tex] \rm{ \frac{2x}{2} = \frac{5y + 1}{2} } \\ [/tex]
Divide both sides of equation 2x = 5y + 1 by 2
Cancel 2 with 2
[tex] \rm{ \frac{\cancel{2}x}{\cancel{2}} = \frac{5y + 1}{2} } \\ [/tex]
[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]
Therefore, the x of 2x - 5y = 1 is [tex] \rm{ \frac{5y + 1}{2} } [/tex]
Solve for y2x - 5y = 1
[tex]\rm{-5y + 2x = 1}\\ [/tex]
Reorder 2x -5y so highest order terms are first
-5y = -2x + 1
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1
[tex]\rm{-5y + 2x - 2x = 1 - 2x}\\[/tex]
Subtract 2x from both sides of the equation
Simply - 5y + 2x -2x = 1 - 2x
Cancel 2x with -2x
Reorder 1 - 2x so highest order terms are first
[tex] \rm{y = - \frac{2x + 1}{5} }\\[/tex]
Move factors not having y from the left side of equation -5y = -2x + 1
[tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} }\\ [/tex]
Divide both sides of equation -5y = -2x +1 by -5
Simplify [tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} } [/tex]
Cancel 5 with -5
Resolve sign on fraction [tex] \rm{\frac{ - 2x + 1}{ - 5} }[/tex]
Therefore, the y of 2x-5y = 1 is [tex]\rm{\frac{ - 2x + 1}{ - 5} } [/tex]
Solve for x3x + 2y = 11
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y
Subtract 2y from the both sides of the equation
Simplify 3x + 2y - 2y = 11 - 2y
Cancel 2y with 2y
Reorder 11 - 2y so highest order terms are first
[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]
Move the factors not having x from the left side of equation 3x = -2y +11
[tex] \rm{ \frac{3x}{3} = \frac{-2y + 11}{3} } \\ [/tex]
Divide both sides of equation 3x = 2y + 11 by 3
Cancel 3 with 3
[tex] \rm{ \frac{\cancel{3}x}{\cancel{3}} = \frac{-2y + 11}{3} } \\ [/tex]
[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]
Therefore, the x for 3x + 2y = 11 is [tex] \rm{ \frac{2y + 11}{3} } [/tex]
Solve for y2y + 3x = 11
Reorder 3x + 2y so highest order terms are first
[tex]\rm{2y + 3x = 11}\\[/tex]
We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11
[tex]\rm{2y + 3x - 3x = 11 - 3x}[/tex]
Subtract 3y from the both sides of the equation
Simplify 2y + 3x - 3x = 11 - 3x
Cancel 3x with - 3x
Reorder 11 - 3x so highest order terms are first
[tex] \rm{y= - \frac{3x + 11}{3} } \\ [/tex]
Move factors not having y from the left side of equation 2y = -3x + 11
[tex] \rm{ \frac{2y}{2} = \frac{-3x + 11}{3} } \\ [/tex]
Divide both sides of equation 2y = -3x + 11 by 2
Cancel 2 with 2
[tex] \rm{ \frac{\cancel{2}y}{\cancel{2}} = \frac{-3x + 11}{3} } \\ [/tex]
[tex] \rm{y = \frac{-3x + 11}{3} } \\ [/tex]
Therefore, the y for 2y + 3x = 11 is [tex] \rm{ \frac{-3x + 11}{3} } [/tex]
What is the slope of line that passes through the points ( 2 , 1 )( 10 , 9 )
Answer:
1.
Step-by-step explanation:
the slope can be calculated as
[tex]slope=\frac{y_2-y_1}{x_2-x_1};[/tex]
according to the formula above:
slope=(9-1)/(10-2)=1.
Suppose the population of a city increasing at a rate of 6. 5% per year. The current population is 35,000. Predict what the population will be in 32 years.
Answer:
262,576.28
Step-by-step explanation:
35,000(1+.065)^32