Which answer shows a reflection across the x-axis?
Answer:
C
Step-by-step explanation:
The key word is x-axis, and since the bottom line is the x, just look for a reflection of it.
Can you please tell me the table of 12?
Answer:
you have the table of the 12in the photo
Step-by-step explanation:
Answer:
12×1=12
12×2=24
12×3=36
12×4=48
12×5=60
12×6=72
12×7=84
12×8=96
12×9=108
12×10=120
In your question
the table of 12 is correct
hope it is helpful to you ☺️☺️☺️☺️☺️
answer for brainlest for 25 points
Answer:
1. 23/4 , 2. 5.555... , 3. 5 1/2 , 4. √28
you want to make them all into decimals so you can compare then easier
23/4 would be 5.75
√28 (just put it in a calculator) would be 5.29
5 1/2 would be 5.5 (make it into a improper fraction 11/2 then do 11/2 and you get 5.5)
and you have 5.555.
so...
5.75
5.29
5.5
5.55555
first is 5.75 it's bigger because of the .(75)
then 5.555 because it's .(55)
then 5.5 because it's .(50)
and the last one 5.(29)
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
Answer:
a.
Step-by-step explanation:
please click the heart and rate excellent and pa brainleist po please ☻❤☺️☺️❤☻
0/5 + 1/5 2/5 3/5 4/5 5/5
Answer:
24/625
Step-by-step explanation:
decimal form is 0.0384
What is the solution to the inequality 7x + 2 < -3x + 1?
Tamia is getting balloons for her father's birthday party. She wants each balloon string to be 6 feet long. At the party store, string is sold by the yard. If Tamia wants to get 59 balloons, how many yards of string will she need?
Answer:
118 yards
Step-by-step explanation:
Tamia is getting balloons for her father's birthday party
She wants each balloon to be 6 feet long
Tamia wants to get 59 balloons
Therefore the yards of string needed can be calculated as follows
= 59×6
= 354 feet to yards
= 118 yards
Hence the number of yards needed is 118 yards
Simplify the expression 4(−3b)(+a) +
8ab ÷ 2a × 4a.
please ans briefly
Answer:
4ab
Step-by-step explanation:
4(-3b)(+a)+8ab÷2a×4a
4(-3ab)+8ab÷2a×4a
-12ab+8ab÷2a×4a
-12ab+4b×4a
-12ab+16ab
16ab-12ab = 4ab
A train is spotted 10 miles south and 8 miles west of an observer at 2:00 pm. At 3:00 pm the train is spotted 5 miles north and 16 miles east of the observer. a. How far did the train travel in the first hour? b. If the train continues at this pace where will it be in relation to the observer at 5:00 pm? Write a function that will give the train's position at any given time c. d. At 2:00 pm a cyclist is traveling due east and is next to the observer. If the cyclist is traveling at 10 mph, do they collide with the train when the bike goes over the train tracks?
Answer:
a. The distance the train travelled in the first hour is approximately 28.3 miles
b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west
c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)
d. The train does not collide with the cyclist when the bike goes over the train tracks
Step-by-step explanation:
a. The given information on the train's motion are;
The location south the train is spotted = 10 miles south and 8 miles west
The time the observer spotted the train = 2:00 pm
The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east
Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour
Making use of the coordinate plane for the two locations the train was spotted, we have;
The initial location of the train = (-10, -8)
The final location of the train = (5, 16)
Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;
[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]
Therefore;
[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]
The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles
b. The speed of the train, v = (Distance travelled by the train)/Time
∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour
The speed of the train in the first hour, v ≈ 28.3 mph
The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;
[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625
c. Distance = Velocity × Time
At 5:00 p.m., we have;
The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours
The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles
Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;
Δx = d₁ × cos(θ)
∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48
The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles
The vertical distance increase in the two hours, Δy is given as follows;
Δy = 56.6 × sin(arctan(0.625)) ≈ 30
The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles
Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)
The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west
c. The function, 'f', that would give the train's position at time-t is given as follows;
The P = f(28.3·t, θ)
Where;
28.3·t = √(x² + y²)
θ = arctan(y/x)
Parametric equations
y - 5 = 0.625·(x - 16)
∴ y = 0.625·x - 10 + 5
The equation of the train's track is therefore, presented as follows;
y = 0.625·x - 5
d = 28.3·t
The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph
Therefore, we have;
y = -10 + 15·t
The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph
Therefore, we have;
x = -8 + 24·t
The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)
d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph
The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8
The distance of the cyclist from the track = 8 miles
The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours
The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)
∴ f(0.8) = (11.2, 2)
At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.
If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.
The location south the train is spotted = 10 miles south and 8 miles west
The time the observer spotted the train = 2:00 pm
The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east
Thus, the difference between the two times the train was spotted,
t = 3:00 p.m. - 2:00 p.m. = 1 hour
What is the distance?The distance is the product of velocity and time.
Distance = Velocity × Time
The initial location of the train = (-10, -8)
The final location of the train = (5, 16)
Therefore the distance the train travelled in the first hour
[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]
d = 3√89
The distance the train travelled in the first hour, d = 28.3 miles
b. The speed of the train, v = (Distance travelled by train)/Time
∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour
The speed of the train in the first hour, v ≈ 28.3 mph
The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;
∴ m = tan(θ) = (5 - (-10))/(16 - (-8))
m = 0.625
c. Distance = Velocity × Time
At 5:00 p.m., we have;
The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours
The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles
Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;
Δx = d₁ × cos(θ)
∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48
The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles
The vertical distance increase in the two hours, Δy is given as follows;
Δy = 56.6 × sin(arctan(0.625)) ≈ 30
The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles
Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)
The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west
c. The function, 'f', that would give the train's position at time-t is given as follows;
The P = f(28.3·t, θ)
28.3·t = √(x² + y²)
θ = arctan(y/x)
Parametric equations
y - 5 = 0.625·(x - 16)
∴ y = 0.625·x - 10 + 5
The equation of the train's track is, therefore, presented as follows;
y = 0.625·x - 5
d = 28.3·t
The y-component of the velocity,
= 3 × √89 mph × sin(arctan(0.625)) = 15 mph
Therefore, we have
y = -10 + 15·t
The x-component of the velocity,
vₓ = 3 × √89 mph × cos(arctan(0.625))
= 24 mph
Therefore, we have;
x = -8 + 24·t
The location of the train at any given time, 't',
f(t) = (-8 + 24·t, -10 + 15·t)
d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph
The distance of the cyclist from the track = The x-intercept
= 5/0.625 = 8
The distance of the cyclist from the track = 8 miles
The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours
The location of the train in 0.8 hours, is f(0.8)
= (-8 + 24×0.8, -10 + 15×0.8)
∴ f(0.8) = (11.2, 2)
therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.
Learn more about distance;
https://brainly.com/question/15172156
2) Avery pays $125 every 5 weeks for basketball training. What is the price per
year for his basketball training? If necessary, round your final answer to the
nearest hundredth's place.
ASAPP!!!!!
Answer:
$1300
Step-by-step explanation:
52/5 = 10.4
$125 * 10.4 = $1300
or another way
125/5 = $25/week
$25 week * 52 weeks = $1300
Sidney is a salesperson. She sold a water heater for $410 and earned 14% commission.
How much commission did Sidney earn?
Answer:
$57.40
Step-by-step explanation:
Hope this helps!!
David has four bags of apples and two bags of mangoes. The first four bags contain 6 apples each and the bags with mangoes contain 3 mangoes each. If David and his friends ate 2 apples from each bag and 2 mangoes from each bag, what is the total number of fruits left over?
Answer:
tal vez sea el fotosíntesis pero no creo jaja
Step-by-step explanation:
pero mañana va?
Answer:
XDXDXDXDXDXDXD YO NO SE LA RESPUESTA :')
Smo answer these and show work plz
Answer:
Step-by-step explanation:
1) multiply the three dimension
V = 7 x 2 x 4 = 56 cm^3
2) find the base area
base area = (9 x 3)/2 = 13,5 km^2
multiply the base area for the height
V = 13,5 x 5 = 67,5 km^3
3) find the trapezoid area
trapezoid area = [(base 1 + base 2) x h]/2 = [(4+6) x 1.7]/2 = 8.5 cm^2
mutiply the trapezoid area for the height that the priam would assume if the base will touch the ground
V = 8.5 x 4 = 34 cm^3
4) find the base area
base area = radius^2 x pi = 2^2 x pi = 12,57 yd^2
multiply the base area for the height
V= 12.57 x 6 = 75.40 yd^3
5) find the base area
base area = 9^2 x pi = 81 x pi = 254.47 ft^2
multiply the base area for the height
V = 254.47 x 5 = 1272.35 ft^3
6) multiply the three dimensions
V = 12 x 11 x 9 = 1188 yd^3
7) find the trapezoid area
trapezoid area = [(12+6) x 6.3]/2 = [20 x 6,3]/2 = 63 in^2
mutiply the trapezoid area for the height that the priam would assume if the base will touch the ground
V = 63 x 16 = 1008 in^3
8) find the base area
base area = (leg1 x leg 2)/2 = (4 x 3)/2 = 6 m^2
multiply the base area for the height
V = 6 x 9 = 54 m^3
Answer:
hope this helps you out good luck with your math
The results of a study exhibit response bias. Select the statement that best describes the bias in the study.
There were not enough subjects who chose to respond to a survey that was sent as part of the study.
The interviewer for the study was the boss of the subjects.
The interviewer for the study did not record the responses of the subjects accurately.
* There was a significant amount of people who declined to participate in the study.
Answer:
"The interviewer for the study did not record the responses of the subjects accurately." I believe this is most pertinent. B, or the boss of the subjects, could have been an answer, but if all members associated in the study exhibit the similar level of response bias based upon superior employers, then the study remains somewhat accurate, but C, or inaccurate record of responses, would remain biased entirely.
Step-by-step explanation:
Answer:
It's C on edge.
Step-by-step explanation:
Did assignment.
Acellus Find the value of x. Round to the nearest tenth. 33° 6 x = [?] PLEASE HELP DONT PUT RANDOM STUFF GETTING REPORTED
Answer:
3.27
Step-by-step explanation:
Let us assume that the values are the side of a right triangle where;
Hypotenuse = 6 (longest)
Angle of elevation = 33 degrees
Required
x = opposite side
Using the trig identity
Sin theta = opp/hyp
Sin 33 = x/6
x = 6sin33
x = 6(0.5446)
x = 3.27
Hence the value of x is 3.27
Note that the values of the sides are assumed.
I cant do this please help me i will give brainliest
Answer:
Here, I graphed this especially for you.
Check attachment.
Rewrite 5 3/7 as an improper fraction.
Answer: 38/7
Step-by-step explanation:
5 3/7
5×7+3
35+3 = 38
38/7
find the perimeter of a figure with the following side lengths: 3x , 5x and 7x ? i need help.
Answer:
15x
Step-by-step explanation:
perimeter is the sum of all sides
3x + 5x + 7x = 15x
question and answer options in photo
please help
zoom in if needed
Answer:
B) 6 ft
Step-by-step explanation:
11 x 34.5 x 25 = 70.5
70.5/12 is about 6
URGENT!!!!!!!! PLEASE HELP ASAP TIMED!!!!!!!!!!!!!!! HELP!!!!!!!!!!!!!!!!!
Answer:
Height of building = 86.9 ft
Step-by-step explanation:
I've drawn a triangle image to depict this question and I have attached it.
From the attached image, we can see that ABC is the height of the building.
We can see the distance from your eye to the ground indicated and also the distance from the horizontal distance from the building to you indicated.
We can use pythagoras theorem to find AB.
AB/57 = tan 55°
AB = 57 × 1.4281
AB = 81.4 ft
Now, total height of the building is AB + BC.
BC = 5.5 ft since B is parallel to your eye and height from there to the ground is 5.5 ft.
Thus;. Height of building = 81.4 + 5.5 = 86.9 ft
a(n+y)=10t+32 solve for y
Step-by-step explanation:
a(n+y) = 10t + 32
n+ y = (10t + 32)/a
y = ((10t+32) /a) -n
Please awnser this correctly! I will make you Brainliest!
Answer:
r=10
Step-by-step explanation:
I used a cone calculator.
Find the sum of the first 39 terms of the following series, to the nearest integer. 2 , 7 , 12 , . . .
Answer:
let'ssssssssss gooooooooooooooooooooooooooooooooooooooooooooooooo
Step-by-step explanation:
Answer:
3783
Step-by-step explanation:
I need this question really badly
Answer:
yeah same for me but with ice cream
an electronic book has a file size of 2.6 MB what is the file size and megabytes of 14 of these electronic books
Please Help, Please Help, Please Help
Answer:
a=76 b=83
Step-by-step explanation:
for a. we divide 6688(area) by 88 to find the width bc 88*w=6688
6688/88 is 76 so a=76
Since 312 is perimeter we have to subtract 73 twice and then divide that by 2 bc 73+73+L+L=312
(312-73-73)/2=83 so b=83
Identify the slope of this graph
please help me !!
Answer:
slope is undefined
Step-by-step explanation:
If the line was horizontal it would be 0 but this is verticle
Answer:
Undefined
Step-by-step explanation:
There's really no equation to this as it is a vertical line.
if it was horizontal it would be 0
but since it is a vertical line you can't really calculate meaning the answer is just undefined.
5Y/ Y-3
+
10/Y^2-Y-6
=
Y/Y+2
Answer:
y=1.110399 or y=−6.782628 or y=−1.327771
Step-by-step explanation:
louis created a square garden with a side length of 5 feet. what is the total area of the garden
Answer:
the answer of the question is 25
COULD SOMEONE HELP ME PLEASE!!!
Answer:
r and s is (2,6) s and t is (-4,-6) r and t are (4,2)
Step-by-step explanation:
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